Physics-
General
Easy

Question

Two wires A blank a n d blank B carry currents as shown in figure. The magnetic interactions

  1. Push i subscript 2 end subscript away from i subscript 1 end subscript    
  2. Pull i subscript 2 end subscript closer to i subscript 1 end subscript    
  3. Turn i subscript 2 end subscript clockwise    
  4. Turn i subscript 2 end subscript counterclockwise    

The correct answer is: Turn i subscript 2 end subscript counterclockwise


    Magnetic field at point P due to i subscript 1 end subscript comma blank B subscript 1 end subscript equals fraction numerator mu subscript 0 end subscript i subscript 1 end subscript over denominator 2 pi x end fraction upward perpendicular to plane paper. Therefore, magnetic force on element P

    F subscript P end subscript equals B subscript 1 end subscript i subscript 2 end subscript d x equals fraction numerator mu subscript 0 end subscript i subscript 1 end subscript i subscript 2 end subscript over denominator 2 pi x end fraction blank d x comma along x-axis
    Magnetic field at point Q due to i subscript 1 end subscript
    B subscript 2 end subscript equals fraction numerator mu subscript 0 end subscript i subscript 1 end subscript over denominator 2 pi x end fraction commadownward perpendicular to plane of paper.
    F subscript Q end subscript equals B subscript 2 end subscript i subscript x end subscript d x equals fraction numerator mu subscript 0 end subscript i subscript 1 end subscript i subscript 2 end subscript over denominator 2 pi x end fraction blank d x comma along (+) x-axis
    So, wire i subscript 2 end subscript will be anticlockwise.

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