Figure shows a square current carrying loop ABCD of side 10 cm and current i = 10 A. The magnetic moment of the loop is

A conducting rod of length l and mass m is moving down a smooth inclined plane of inclination qwith constant velocity v in fig. A current I is flowing in the conductor in a direction perpendicular to paper inwards. A vertically upward magnetic field B exists in space. Then magnitude of magnetic field B is

The square loop ABCD, carrying a current I, is placed in a uniform magnetic field B, as shown. The loop can rotate about the axis XX. The plane of the loop makes an angle with the direction of B. Through what angle will the loop rotate by itself before the torque on it becomes zero–

 In the above reaction Z is

In the given figure, and , then the value of is

Hence Choice 3 is correct

Compute the value of x in the given figure.

Compute the value of x in the given figure.

The value of x=88^o

Compute the value of x in the given figure.

Hence option B is correct

Compute the value of x in the given figure.

Choice 4 is correct

In the given figure, if and then the value of is

Hence 85^o is correct option

In figure, if and y : z = 3 : 7, x = ?

Hence x=126 choice 4 is correct

In figure, if and = ?

Hence 92^o
is correct choice

In figure, sides QP and RQ of are produced to points S and T respectively. If and =?

Hence choice A  is correct

A conductor PQ carries a current 'i' is placed perpendicular to a long conductor XY carrying a current I. The direction of force on PQ will be :–

A circular current loop of radius a is placed in a radial field B as shown. The net force acting on the loop is

All straight wires are very long. Both AB and CD are arcs of the same circle, both subtending right angles at the centre O. Then the magnetic field at O is–