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Physics-

General

Easy

Question

For the circuit shown in figure the charge on 4 $mu$ F capacitor is

40 $μ$ C
30 $μ$ C
24 $μ$ C
54 $μ$ C

The correct answer is: 24 $mu$ C

Combined capacity of $1 blank mu F$ and $5 mu F blank$ = 1 + 5= $6 blank mu F$
Now, $4 mu F blank$ and $6 mu F$ are in series.
$therefore blank fraction numerator 1 over denominator C subscript s end subscript end fraction equals fraction numerator 1 over denominator 4 end fraction plus fraction numerator 1 over denominator 6 end fraction plus fraction numerator 3 plus 2 over denominator 12 end fraction equals fraction numerator 5 over denominator 12 end fraction$
$C subscript s end subscript equals fraction numerator 12 over denominator 5 end fraction mu F$
Charge in the arm containing $4 mu F blank$ capacitor is
$q equals C subscript s end subscript cross times V equals fraction numerator 12 over denominator 5 end fraction cross times 10 equals 24 blank mu C$

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