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Physics-

General

Easy

Question

If a 70 kg man is lowering a 20 kg mass with an acceleration 2 m/s² the reading on the machine is:

54 kg
64 kg
66 kg
70 kg

The correct answer is: 54 kg

$F equals W minus T$
$T equals W minus F$
$equals 20 cross times 10 minus 20 cross times 2 equals 160 N$
$R equals W minus T$
$equals 700 minus 160 equals 540 N equals 54 k g$

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