Physics-
General
Easy

Question

Two blocks of masses 4kg and 2kg are connected by means of a string as shown in the figure. The coefficient of friction between the plane and the two blocks are 0.75 and 0.25 respectively. These blocks slip down an inclined plane with an angle of inclination 37degree The common acceleration of the blocks in m divided by s to the power of 2 end exponent is:open parentheses T a n invisible function application 37 to the power of ring operator end exponent equals fraction numerator 3 over denominator 4 end fraction close parentheses

  1. 1.3    
  2. 2.6    
  3. 0.13    
  4. 13    

The correct answer is: 1.3



    m subscript 1 end subscript equals 4 k g comma m subscript 2 end subscript equals 2 k g
    mu subscript 1 end subscript equals 0.76 comma mu subscript 2 end subscript equals 0.25
    F minus mu m g equals F to the power of 1 end exponent
    open parentheses 4 plus 2 close parentheses g sin invisible function application 3 7 minus open parentheses 0.75 cross times 4 plus 0.25 cross times 2 close parentheses g cos invisible function application 3 7 equals open parentheses 4 plus 2 close parentheses a
    rightwards double arrow a equals 1.3 m divided by s to the power of 2 end exponent

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