Physics-
General
Easy

Question

In a thin rectangular metallic strip a constant current I flows along the positive x-direction, as shown in the figure. The length, width and thickness of the strip are l, w and d, respectively. A uniform magnetic field B rho is applied on the strip along the positive y-direction. Due to this, the charge carries experience a net deflection along the z-direction. This results in accumulation of charge caries on the surface PQRS and appearance of equal and opposite charges on the face opposite to PQRS. A potential difference along the z-direction is thus developed. Charge accumulation continues until the magnetic force is balanced by the electric force. The current is assumed to be uniformly distributed on the cross section of the strip and carried by electrons.

Consider two different metallic strips (1 and 2) of same dimensions (length l, width w and thickness d) with carrier densities n subscript 1 end subscript and n subscript 2 end subscript , respectively. Strip 1 is placed in magnetic field B subscript 1 end subscript and strip 2 is placed in magnetic field B subscript 2 end subscript , both along positive y-directions. Then V subscript 1 end subscript and V subscript 2 end subscript are the potential differences developed between K and M in strips 1 and 2, respectively. Assuming that the current I is the same for both the strips, the correct option (S) is (are).

  1. If B subscript 1 end subscript equals B subscript 2 end subscript and n subscript 1 end subscript equals 2 n subscript 2 end subscript, then V subscript 2 end subscript equals 2 V subscript 1 end subscript    
  2. If B subscript 1 end subscript equals B subscript 2 end subscript and n subscript 1 end subscript equals 2 n 2, then V subscript 2 end subscript equals V subscript 1 end subscript    
  3. If B subscript 1 end subscript equals 2 B subscript 2 end subscript and n subscript 1 end subscript equals n subscript 2 end subscript, then V subscript 2 end subscript equals 0.5 V subscript 1 end subscript    
  4. If B subscript 1 end subscript equals 2 B subscript 2 end subscript and n subscript 1 end subscript equals n subscript 2 end subscript, then V subscript 2 end subscript equals V subscript 1 end subscript    

The correct answer is: If B subscript 1 end subscript equals B subscript 2 end subscript and n subscript 1 end subscript equals 2 n subscript 2 end subscript, then V subscript 2 end subscript equals 2 V subscript 1 end subscript


    I subscript 1 end subscript equals I subscript 2 end subscript
    table row cell n subscript 1 end subscript e A subscript 1 end subscript v subscript d subscript 1 end subscript end subscript equals n subscript 2 end subscript e A subscript 2 end subscript v subscript d subscript 2 end subscript end subscript end cell row cell rightwards double arrow n subscript 1 end subscript v subscript d subscript 1 end subscript end subscript equals n subscript 2 end subscript v subscript d subscript 2 end subscript end subscript end cell row cell n subscript 1 end subscript fraction numerator V subscript 1 end subscript over denominator w subscript 1 end subscript B subscript 1 end subscript end fraction equals n subscript 2 end subscript fraction numerator V subscript 2 end subscript over denominator w subscript 2 end subscript B subscript 2 end subscript end fraction end cell row cell text end text text I end text text f end text text end text B subscript 1 end subscript equals B subscript 2 end subscript text end text text t end text text h end text text e end text text n end text text end text n subscript 1 end subscript V subscript 1 end subscript equals n subscript 2 end subscript V subscript 2 end subscript end cell end table

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