Physics-
General
Easy
Question
In experiment for measuring surface tension by capillary rise method, reading or positions A,B, C and D for internal diameter of capillary tube are given as under
Mean intenal radius of capillary is
- 0.002cm
- 0.003cm
- 0.004cm
- 0.005cm
The correct answer is: 0.002cm
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When jet of liquid strikes a fixed or moving surface, it exerts thrust on it due to rate of change of momentum. F =
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When jet of liquid strikes a fixed or moving surface, it exerts thrust on it due to rate of change of momentum. F =
If surface is free and starts moving due to thrust of liquid, then at any instant, the above equation gets modified based on relative change of momentum with respect to surface. Let any instant the velocity of surface is u, then above equation becomes –
Based on above concept, in the below given figure, if the cart is frictionless and free to move in horizontal direction, then answer the following :Given cross–section area of jet velocity of jet = 10 m/s, density of liquid = 1000 kg/ , Mass of cart M = 10 kg: The time at which velocity of cart becomes 2m/s, is equal to:
When jet of liquid strikes a fixed or moving surface, it exerts thrust on it due to rate of change of momentum. F =
If surface is free and starts moving due to thrust of liquid, then at any instant, the above equation gets modified based on relative change of momentum with respect to surface. Let any instant the velocity of surface is u, then above equation becomes –
Based on above concept, in the below given figure, if the cart is frictionless and free to move in horizontal direction, then answer the following :Given cross–section area of jet velocity of jet = 10 m/s, density of liquid = 1000 kg/ , Mass of cart M = 10 kg: The time at which velocity of cart becomes 2m/s, is equal to:
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When jet of liquid strikes a fixed or moving surface, it exerts thrust on it due to rate of change of momentum. F =
If surface is free and starts moving due to thrust of liquid, then at any instant, the above equation gets modified based on relative change of momentum with respect to surface. Let any instant the velocity of surface is u, then above equation becomes –
Based on above concept, in the below given figure, if the cart is frictionless and free to move in horizontal direction, then answer the following :Given cross–section area of jet velocity of jet = 10 m/s, density of liquid = 1000 kg/ , Mass of cart M = 10 kg: In the above problem, what is the acceleration of cart at this instant –
When jet of liquid strikes a fixed or moving surface, it exerts thrust on it due to rate of change of momentum. F =
If surface is free and starts moving due to thrust of liquid, then at any instant, the above equation gets modified based on relative change of momentum with respect to surface. Let any instant the velocity of surface is u, then above equation becomes –
Based on above concept, in the below given figure, if the cart is frictionless and free to move in horizontal direction, then answer the following :Given cross–section area of jet velocity of jet = 10 m/s, density of liquid = 1000 kg/ , Mass of cart M = 10 kg: In the above problem, what is the acceleration of cart at this instant –
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When jet of liquid strikes a fixed or moving surface, it exerts thrust on it due to rate of change of momentum. F =
If surface is free and starts moving due to thrust of liquid, then at any instant, the above equation gets modified based on relative change of momentum with respect to surface. Let any instant the velocity of surface is u, then above equation becomes –
Based on above concept, in the below given figure, if the cart is frictionless and free to move in horizontal direction, then answer the following :Given cross–section area of jet velocity of jet = 10 m/s, density of liquid = 1000 kg/ , Mass of cart M = 10 kg: Velocity of cart at t = 10 s. is equal to:
When jet of liquid strikes a fixed or moving surface, it exerts thrust on it due to rate of change of momentum. F =
If surface is free and starts moving due to thrust of liquid, then at any instant, the above equation gets modified based on relative change of momentum with respect to surface. Let any instant the velocity of surface is u, then above equation becomes –
Based on above concept, in the below given figure, if the cart is frictionless and free to move in horizontal direction, then answer the following :Given cross–section area of jet velocity of jet = 10 m/s, density of liquid = 1000 kg/ , Mass of cart M = 10 kg: Velocity of cart at t = 10 s. is equal to:
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When jet of liquid strikes a fixed or moving surface, it exerts thrust on it due to rate of change of momentum. F =
If surface is free and starts moving due to thrust of liquid, then at any instant, the above equation gets modified based on relative change of momentum with respect to surface. Let any instant the velocity of surface is u, then above equation becomes –
Based on above concept, in the below given figure, if the cart is frictionless and free to move in horizontal direction, then answer the following :Given cross–section area of jet velocity of jet = 10 m/s, density of liquid = 1000 kg/ , Mass of cart M = 10 kg: Initially (t = 0) the force on the cart is equal to :
When jet of liquid strikes a fixed or moving surface, it exerts thrust on it due to rate of change of momentum. F =
If surface is free and starts moving due to thrust of liquid, then at any instant, the above equation gets modified based on relative change of momentum with respect to surface. Let any instant the velocity of surface is u, then above equation becomes –
Based on above concept, in the below given figure, if the cart is frictionless and free to move in horizontal direction, then answer the following :Given cross–section area of jet velocity of jet = 10 m/s, density of liquid = 1000 kg/ , Mass of cart M = 10 kg: Initially (t = 0) the force on the cart is equal to :
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