In figure, one car at rest and velocity of the light from head light is $c$ , tehn velocity of light from head light for the moving car at velocity $v$ , would be

A particle of mass $m$ is initially situated at the point $P$ inside a hemispherical surface of radius $r$ as shown in figure. A horizontal acceleration of magnitude $a subscript 0 end subscript$ is suddenly produced on the particle in the horizontal direction. If gravitational acceleration is neglected, the time taken by particle to touch the sphere again is

A cyclist starts from the centre $O$ of a circular park of radius 1 km, reaches the edge $P$ of the park, then cycles along the circumference and returns to the point $O$ as shown in figure. If the round trip takes 10 min, the net displacement and average speed of the cyclist (in metre and kilometer per hour) are

A the instant a motor bike starts from rest in a given direction, a car overtakes the motor bike, both moving in the same direction. The speed-time graphs for motor bike and car are represented by $O A B$ and $C D$ respectively Then

Assertion : Owls can move freely during night.
Reason : They have large number of rods on their retina.

A particle shows distance-time curve as given in this figure. The maximum instantaneous velocity of the particle is around the point

Maths-

The area bounded by y=3x and $y equals x to the power of 2 end exponent$ is

So now here we can say that using the integration method, the area of the region bounded by the given curves is 4.5. The equation A = ∫ab f(x) dx gives the area under the curve y = f(x) and x-axis. The bounding values for the curve with respect to the x-axis are shown here as a and b.

The area bounded by y=3x and $y equals x to the power of 2 end exponent$ is

Maths-General

Maths-

The area bounded by $y equals x squared plus 2 comma$ X- axis, x=1 and x=2 is

So now here we can say that using the integration method, the area of the region bounded by the given curve and the lines is 13/3. The equation A = ∫ab f(x) dx gives the area under the curve y = f(x) and x-axis. The bounding values for the curve with respect to the x-axis are shown here as a and b.

The area bounded by $y equals x squared plus 2 comma$ X- axis, x=1 and x=2 is

Maths-General

maths-

If $Cos space 2 theta times Cos space 3 theta times cos space theta equals 1 fourth text for end text 0 less than theta less than pi$ then $theta$ =

maths-General

The $x minus t$ graph shown in the figure represents

For the velocity-time graph shown in figure below the distance covered by the body in last two seconds of its motion is what fraction of the total distance covered by it in all the seven seconds

A particle starts from rest at $t equals 0$ and undergoes an acceleration $a$ in $m s to the power of negative 2 end exponent$ with time $t$ in second which is as shownWhich one of the following plot represents velocity $v$ in $m s to the power of negative 1 end exponent blank v e r s u s$ time $t$ in second?

A body is at rest at $x equals 0$ . At $t equals 0$ , it starts moving in the positive $x$ -direction with a constant acceleration. At the same instant another body passes through $x equals 0$ moving in the positive $x$ -direction with a constant speed. The position of the first body is given by $x subscript 1 end subscript left parenthesis t right parenthesis$ after time ‘ $t$ ’ and that of the second body by $x subscript 2 end subscript left parenthesis t right parenthesis$ after the same time interval. Which of the following graphs correctly describes $left parenthesis x subscript 1 end subscript minus x subscript 2 end subscript right parenthesis$ as a function of time ‘ $t$ ’

maths-

General solution of $2 to the power of x equals n x end exponent plus 2 to the power of cos space x end exponent equals 2 to the power of 1 minus fraction numerator 1 over denominator square root of 2 end fraction end exponent$ is

maths-General

In the following graph, distance travelled by the body in metres is