Physics-
General
Easy

Question

 In the above radioactive decay C is stable nucleus. Then:

  1. rate of decay of A will first increase and then decrease    
  2. number of nuclei of B will first increase and then decrease    
  3. if lambda subscript 2 end subscript greater than lambda subscript 1 subscript 1 end subscript end subscript, then activity of B will always be higher than activity of A    
  4. if lambda subscript 1 end subscript greater than lambda subscript 2 subscript 1 end subscript end subscript, then number of nucleus of C will always be less than number of nucleus of B.    

The correct answer is: number of nuclei of B will first increase and then decrease

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