Physics-
General
Easy

Question

In the circuit shown in figure : R subscript 1 end subscript equals 10 capital omega comma L equals fraction numerator square root of 3 over denominator 10 end fraction H comma R subscript 2 end subscript equals 20 capital omega and C equals fraction numerator square root of 3 over denominator 2 end fraction mF. Current in L minus R subscript 1 end subscript circuit is I subscript 1 end subscript in C minus R subscript 2 end subscript circuit is I subscript 2 end subscript and the main current is I Phase different between I subscript 1 end subscript and I subscript 2 end subscript is

  1.    
  2. 90°    
  3. 180°    
  4. 60°    

The correct answer is: 60°

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Z equals square root of R to the power of 2 end exponent plus open parentheses W L minus fraction numerator 1 over denominator W C end fraction close parentheses to the power of 2 end exponent end root and I subscript 0 end subscript equals fraction numerator V subscript 0 end subscript over denominator Z end fraction

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Z equals square root of R to the power of 2 end exponent plus open parentheses W L minus fraction numerator 1 over denominator W C end fraction close parentheses to the power of 2 end exponent end root and I subscript 0 end subscript equals fraction numerator V subscript 0 end subscript over denominator Z end fraction

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Z equals square root of R to the power of 2 end exponent plus open parentheses W L minus fraction numerator 1 over denominator W C end fraction close parentheses to the power of 2 end exponent end root and I subscript 0 end subscript equals fraction numerator V subscript 0 end subscript over denominator Z end fraction

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