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Physics-

General

Easy

Question

In the given figure, the position time graph of a particle of mass 0.1 kg is shown. The impulse at t= 2sec is

$0.2 k g m {s e c}^{- 1}$
$- 0.2 k g m {s e c}^{- 1}$
$0.1 k g m {s e c}^{- 1}$
$- 0.4 k g m {s e c}^{- 1}$

The correct answer is: $0.2 blank k g blank m s e c to the power of negative 1 end exponent$

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