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Physics-

General

Easy

Question

The current $i subscript 1 end subscript$ and $i subscript 2 end subscript$ through the resistor $R subscript 1 end subscript open parentheses equals 10 capital omega close parentheses$ and $R subscript 2 end subscript open parentheses equals 30 capital omega close parentheses$ in the circuit diagram with $E subscript 1 end subscript equals 3 V comma E subscript 2 end subscript equals 3 blank a n d E subscript 3 end subscript equals 2 V$ are respectively.

02.A, 0.1A
0.4A, 0.2A
0.1A, 0.2A
0.2A, 0.4A

The correct answer is: 02.A, 0.1A

In closed loop EFGDE

$i subscript 2 end subscript R subscript 2 end subscript equals E subscript 2 end subscript$
$i subscript 2 end subscript cross times 30 equals 3$
$i subscript 2 end subscript equals 0.1 A$
In closed loop ABCEA
$negative i subscript 1 end subscript R subscript 1 end subscript minus E subscript 1 end subscript plus E subscript 2 end subscript plus E subscript 3 end subscript equals 0$
$negative i subscript 1 end subscript cross times 10 minus 3 plus 3 plus 2 equals 0$
$i subscript 1 end subscript equals 0.2 A$

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