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Physics-

General

Easy

Question

The equivalent capacitance between the points $A a n d B$ in the following circuit is

1 $μ F$
2 $μ F$
4 $μ F$
8 $μ F$

The correct answer is: 1 $mu F$

The two capacitors each of value 1.5 $mu F$ are in parallel. So, their equivalent capacitance

Now, three capacitors each of value $3 mu F$ are in series. Hence, their equivalent capacitance is given by
$fraction numerator 1 over denominator C end fraction equals fraction numerator 1 over denominator 3 end fraction plus fraction numerator 1 over denominator 3 end fraction plus fraction numerator 1 over denominator 3 end fraction$
or $fraction numerator 1 over denominator C end fraction blank equals fraction numerator 3 over denominator 3 end fraction$
or $c equals 1 mu F$

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