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General
Easy

Question

The following diagram indicates the energy levels of a certain atom when the system moves from 2 E level to E, emitting a photon of wavelength lambda. The wavelength of photon produced during its transition from fraction numerator 4 E over denominator 3 end fraction level to E is

  1. lambda divided by 3    
  2. 3 lambda divided by 4    
  3. 4 lambda divided by 3    
  4. 3 lambda    

The correct answer is: 3 lambda


    2 E minus E equals fraction numerator h c over denominator lambda end fraction rightwards double arrow E equals fraction numerator h c over denominator lambda end fraction
    fraction numerator 4 E over denominator 3 end fraction minus E equals fraction numerator h c over denominator lambda to the power of ´ end exponent end fraction rightwards double arrow fraction numerator E over denominator 3 end fraction equals fraction numerator h c over denominator lambda to the power of ´ end exponent end fraction blank therefore fraction numerator lambda to the power of ´ end exponent over denominator lambda end fraction equals 3 rightwards double arrow lambda to the power of ´ end exponent equals 3 lambda

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