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Easy
Question
Three processes form a thermodynamic cycle as shown on P-V diagram for an ideal gas Process 1 → 2 takes place at constant temperature (300K).Process 
takes place at constant volume During this process 40J of heat leaves the system Process 
is adiabatic and temperature T3 is 275K. Work done by the gas during the process
is
- -40J
- -20J
- +40J
- +20J
The correct answer is: -40J
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