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Physics-

General

Easy

Question

Two thin lenses of focal lengths 1 f and 2 f are in contact and coaxial. The combination is equivalent to a single lens of power

$\frac{f_{1} f_{2}}{f_{1} + f_{2}}$
$\frac{1}{2} (f_{1} + f_{2})$
$\frac{f_{1} + f_{2}}{f_{1} f_{2}}$
$\sqrt{f_{1} f_{2}}$

The correct answer is: $fraction numerator f subscript 1 end subscript plus f subscript 2 end subscript over denominator f subscript 1 end subscript f subscript 2 end subscript end fraction$

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Methanol and acetone can be separated by:

Methanol and acetone can be separated by:

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Decreasing order of solubility of following compounds is:

Decreasing order of solubility of following compounds is:

chemistry-General

Which of the following statement is correct about tropolone?

Which of the following statement is correct about tropolone?

chemistry-General

parallel

In which case first has higher solubility than second?
I) Phenol, Benzene
II) Nitrobenzene, Phenol
III) o–Hydroxybenzaldehyde, p–Hydroxy benzaldehyde
IV) CH₃CHO, CH₃–O–CH₃
V) o–Nitrophenol, p–Nitrophenol
VI)

In which case first has higher solubility than second?
I) Phenol, Benzene
II) Nitrobenzene, Phenol
III) o–Hydroxybenzaldehyde, p–Hydroxy benzaldehyde
IV) CH₃CHO, CH₃–O–CH₃
V) o–Nitrophenol, p–Nitrophenol
VI)

chemistry-General

If $alpha$ and $beta$ are the eccentric angles of the extremities of a focal chord of an ellipse, then the eccentricity of the ellipse is

If $alpha$ and $beta$ are the eccentric angles of the extremities of a focal chord of an ellipse, then the eccentricity of the ellipse is

The point $left parenthesis a comma 2 a right parenthesis$ is an interior point of the region bounded by the parabola $y to the power of 2 end exponent equals 16 x$ and the double ordinate through the focus Then ‘a’ belongs to the open interval

The point $left parenthesis a comma 2 a right parenthesis$ is an interior point of the region bounded by the parabola $y to the power of 2 end exponent equals 16 x$ and the double ordinate through the focus Then ‘a’ belongs to the open interval

parallel

Through the vertex $O$ ofthe parabola $y to the power of 2 end exponent equals 4 a x$ chords OP, OQ are drawn at right angles to each other If the locus of mid points of the chord PQ is a parabola then its vertex is

Through the vertex $O$ ofthe parabola $y to the power of 2 end exponent equals 4 a x$ chords OP, OQ are drawn at right angles to each other If the locus of mid points of the chord PQ is a parabola then its vertex is

The area of the trapezium whose vertices lie on the parabola $y to the power of 2 end exponent equals 4 x$ and its diagonals pass through $left parenthesis 1 , 0 right parenthesis$ and having length $fraction numerator 25 over denominator 4 end fraction$ units each is

The area of the trapezium whose vertices lie on the parabola $y to the power of 2 end exponent equals 4 x$ and its diagonals pass through $left parenthesis 1 , 0 right parenthesis$ and having length $fraction numerator 25 over denominator 4 end fraction$ units each is

The Locus of centre of circle which touches given circle externally and the given line is

The Locus of centre of circle which touches given circle externally and the given line is

parallel

If the length of tangents from $left parenthesis a comma b right parenthesis$ to the circles $x to the power of 2 end exponent plus y to the power of 2 end exponent minus 4 x minus 5 equals 0$ and $x to the power of 2 end exponent plus y to the power of 2 end exponent plus 6 x minus 2 y plus 6 equals 0$ are equal then $10 a minus 2 b equals$

If the length of tangents from $left parenthesis a comma b right parenthesis$ to the circles $x to the power of 2 end exponent plus y to the power of 2 end exponent minus 4 x minus 5 equals 0$ and $x to the power of 2 end exponent plus y to the power of 2 end exponent plus 6 x minus 2 y plus 6 equals 0$ are equal then $10 a minus 2 b equals$

The line $2 x plus 3 y equals 1$ cuts the circle $x to the power of 2 end exponent plus y to the power of 2 end exponent equals 4$ in $P$ and Q Then the equation of the smaller circle passing through $P$ and $Q$

The line $2 x plus 3 y equals 1$ cuts the circle $x to the power of 2 end exponent plus y to the power of 2 end exponent equals 4$ in $P$ and Q Then the equation of the smaller circle passing through $P$ and $Q$

If the angle between two equal circles with centres $left parenthesis 3 , 10 right parenthesis$ , $left parenthesis negative 5 , 4 right parenthesis blank$ is 12 $0 to the power of blank$ then the radius of the circle is

If the angle between two equal circles with centres $left parenthesis 3 , 10 right parenthesis$ , $left parenthesis negative 5 , 4 right parenthesis blank$ is 12 $0 to the power of blank$ then the radius of the circle is

parallel

The equation of the circle passing through the origin and the points of intersection of the circles $x to the power of 2 end exponent plus y to the power of 2 end exponent minus 4 x minus 6 y minus 3 equals 0 comma$ $x to the power of 2 end exponent plus y to the power of 2 end exponent plus 4 x minus 2 y minus 4 equals 0$

The equation of the circle passing through the origin and the points of intersection of the circles $x to the power of 2 end exponent plus y to the power of 2 end exponent minus 4 x minus 6 y minus 3 equals 0 comma$ $x to the power of 2 end exponent plus y to the power of 2 end exponent plus 4 x minus 2 y minus 4 equals 0$

The locus of a point such that difference of the squares of the tangents from it to two given circles is constant, is given by

The locus of a point such that difference of the squares of the tangents from it to two given circles is constant, is given by

Radical centre of the circles $x to the power of 2 end exponent plus y to the power of 2 end exponent plus 4 x minus 6 y minus 12 equals 0 comma$ $x to the power of 2 end exponent plus y to the power of 2 end exponent plus 4 x minus 6 y plus 2 equals 0 comma$ $x to the power of 2 end exponent plus y to the power of 2 end exponent plus 4 x minus 6 y plus 4 equals 0$

Radical centre of the circles $x to the power of 2 end exponent plus y to the power of 2 end exponent plus 4 x minus 6 y minus 12 equals 0 comma$ $x to the power of 2 end exponent plus y to the power of 2 end exponent plus 4 x minus 6 y plus 2 equals 0 comma$ $x to the power of 2 end exponent plus y to the power of 2 end exponent plus 4 x minus 6 y plus 4 equals 0$

parallel

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