Maths-
General
Easy

Question

Solve 16(4 - 3m) = 96(fraction numerator negative m over denominator 2 end fraction
  + 1)

hintHint:

An equation with variables on both sides of the "equal to" sign i.e. on LHS and RHS can be solved by first simplifying both the sides (Opening up the brackets, addition, subtraction, i.e. if any) and then all the variables are taken on 1 side of the equation and all the constants i.e. numbers on the other side. Both sides are then simplified further and the solution is obtained.

The correct answer is: The given system of equations have no solution.


    Step-by-step solution:-
    16(4 - 3m) = 96(fraction numerator negative m over denominator 2 end fraction + 1)
                                                                         ∴ (16 × 4) - (16 × 3m) = (96 × fraction numerator negative m over denominator 2 end fraction) + (96 × 1) ..................... [Distributive property- a (m+n) = am + an]
                                                                                             ∴ 64 - 48m = -48m + 96
                                                                                             ∴ -48m + 48m = 96 - 64 …....................... (Taking all variables and constants on either                                                                                                                                                                                                         sides of the equation)
                                                                                                       ∴ 0 = 32
    Since, after simplifying the given equation, the variable gets eliminated and LHS ≠ RHS, the given set of equations have no solution. i.e. for no value of m, the given equation will be satisfied.
    Final Answer:-
    ∴ The given system of equations have no solution.

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