Question
On combustion of propane, reaction:
If 200gms of propane is burned, then how many grams of water is produced?
- 327.27 grams
- 430.3 grams
- 210.5 grams
- 100.1 grams
Hint:
For the overall reaction, it is important to calculate the molecular mass first.
The correct answer is: 327.27 grams
- On combustion of propane reaction, if 200 grams of propane is burned, then 327.2 grams of water is produced. The reaction formed here is C3H8 + 6O2 = 3CO2 + 4H2O.
- When there is complete combustion, the molecular mass is calculated as atomic mass multiplied by the number of atoms. Here, the atomic mass of carbon is 12 and that of hydrogen is 1. Thus, the molecular mass turns out to be 12 X 3 + 1 X 8 = 44 grams. The molar quantity of propane turns out to be 44 grams.
- n of propane is 200 divided by 44 which gives 4.5 mol. Now, as we have 4 equivalents w.r.t water. So, we get 4.5 X 4 which gives 18 moles and mass comes out to be 326.7 grams.
Number of moles are calculated as mass of substance divided by mass of one mole.
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