Question
Suppose a goalie kicks a soccer ball. The ball travels in a parabolic path from point (0,0) to (57,0). Consider a quadratic function in vertex form for the path of the ball. Which values can you determine? What values are you unable to determine? Explain.
Hint:
The vertex form of a quadratic function is
f(x) = a(x – h)2 + k
Where a, h, and k are constants. Here, h represents horizontal translation, a represents vertical translation and (h,k) is the vertex of the parabola. Also, a represents the Vertical stretch/shrink of the parabola and if a is negative, then the graph is reflected over the x-axis.
The correct answer is: we will be able to determine the x-coordinate(h) of the vertex only. The value of y-coordinate(k) and “a” of the equation of the path of the ball
a)
Let’s say that the equation of the path of the ball is y = a(x – h)2 + k
The ball travels from (0,0) to (57,0).
Put (0,0) in the equation y = a(x – h)2 + k
0 = a(0-h)2 + k
k = -ah2 …….(1)
Put (57,0) in the equation y = a(x – h)2 + k
0 = a(57-h)2 + k
a(3249 + h2 - 114h) - ah2 = 0 ( from equation 1)
3249a +ah2 - 114ha - ah2 = 0
3249a = 114ha
2h = 57
h = 28.5
Final Answer:
Hence, we will be able to determine the x-coordinate(h) of the vertex only. The value of y-coordinate(k) and “a” of the equation of the path of the ball.
Put (57,0) in the equation y = a(x – h)2 + k
Final Answer:
Hence, we will be able to determine the x-coordinate(h) of the vertex only. The value of y-coordinate(k) and “a” of the equation of the path of the ball.
A polynomial function is referred to as quadratic if it has one or more variables and a variable with a maximum exponent of two. It is sometimes referred to as the polynomial of degree 2 since the greatest degree term in a quadratic function is of the second degree.
The locations whose coordinates are of the form are connected by the parent quadratic function, which has the form f(x) = x2 (number, number2). The parent quadratic function joins the places whose coordinates have the form f(x) = x2 (number, number2). This function, which generally has the form f(x) = a (x - h)2 + k, can be transformed to take the form f(x) = ax2 + bx + c.