The alkyl halide is converted into an alcohol by

$integral subscript 0 superscript 100 sin invisible function application left parenthesis x minus left square bracket x right square bracket right parenthesis pi d x$

So here we used the concept of integrals of special functions and simplified it. We can also solve it manually but it will take lot of time to come to final answer hence we used the substitution method to solve. The integral of the given function is $integral subscript 0 superscript 100 sin invisible function application left parenthesis straight x minus left square bracket straight x right square bracket right parenthesis πdx equals 200 over straight pi$ .

$integral subscript 0 superscript 100 sin invisible function application left parenthesis x minus left square bracket x right square bracket right parenthesis pi d x$

$integral subscript negative pi divided by 2 end subscript superscript pi divided by 2 end superscript sin invisible function application vertical line x vertical line d x equals$

So here we used the concept of integrals of special functions and simplified it. We can also solve it manually but it will take lot of time to come to final answer hence we used the modulus function to solve. The integral of the given function is $integral subscript negative pi divided by 2 end subscript superscript pi divided by 2 end superscript sin invisible function application vertical line x vertical line d x equals 2$

$integral subscript negative pi divided by 2 end subscript superscript pi divided by 2 end superscript sin invisible function application vertical line x vertical line d x equals$

chemistry-

Which of the following plots represents correctly variation of equivalent conductance $open parentheses logical and close parentheses$ with dilution for a strong electrolyte ?

chemistry-General

if $a to the power of 2 end exponent plus b to the power of 2 end exponent plus c to the power of 2 end exponent equals a b plus b c plus c a$ then the triangle is

Find x in the given figure .

Two masses $M subscript 1 end subscript$ and $M subscript 2 end subscript$ connected by means of a string which is made to pass over light, smooth pulley are in equilibrium on a fixed smooth wedge as shown in figure. If $theta equals 60 to the power of ring operator end exponent$ and $alpha equals 30 to the power of ring operator end exponent$ , the ratio of $M subscript 1 end subscript$ to $M subscript 2 end subscript$ is

A sphere of mass $m$ is held between two smooth inclined walls. For $s i n invisible function application 37 to the power of ring operator end exponent equals 3 divided by 5$ . The normal reaction of the wall(2) is equal to:

Two blocks ' A ' and ' B ' each of mass ' m ' are placed on a smooth horizontal surface. Two horizontal force F and 2 F are applied on both the blocks ' A ' and ' B ' respectively as shown in figure. The block A does not slide on block B. Then the normal reaction acting between the two blocks is:

A light smooth inextensible string connected with two identical particles each of mass m, passes through a light ring R. If a force F pulls ring, the relative acceleration between the particles has magnitude :

Two light strings connect three particles of masses $m subscript 1 end subscript comma m subscript 2 end subscript$ and $m subscript 3 end subscript$ . If $m subscript 3 end subscript$ moves with an acceleration a as shown in the figure, the ratio of tension in the strings 1 and 2 is

Two forces $stack F with rightwards arrow on top subscript 1 end subscript$ and $stack F with rightwards arrow on top subscript 2 end subscript$ act at the ends of a massless string opposite to each other. Then

What is the relation between velocities of points A and B in the given figure.

What is the relation between velocities of points A and B in the given figure.

In the figure acceleration of bodies A, B and C are shown with directions. Values b and c are w.r.t ground whereas a is acceleration of block A w.r.t wedge C. Acceleration of block A w.r.t ground is