Physics-
General
Easy

Question

The binding energies per nucleon of Li to the power of 7 and He to the power of 4 are 5.6 MeV and 7.06 MeV respectively, then the energy of the reaction L i to the power of 7 plus p equals 2 open square brackets 2 to the power of H e to the power of 4 end exponent close square brackets  will be

  1. 17.28 MeV
  2. 39.2 MeV
  3. 28.24 MeV
  4. 1.46 MeV

The correct answer is: 17.28 MeV


    The reaction is

    table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em end attributes row cell 3 to the power of Li to the power of 7 end exponent plus subscript 1 straight P to the power of 1 not stretchy rightwards arrow 2 open parentheses 2 to the power of He to the power of 4 end exponent close parentheses end cell row cell therefore straight E subscript straight p equals 2 straight E open parentheses 2 to the power of He to the power of 4 end exponent close parentheses straight E subscript left parenthesis Li right parenthesis end subscript end cell row cell equals 2 left parenthesis 4 cross times 7.06 right parenthesis minus 7 cross times 5.6 end cell row cell equals 56.48 minus 39.2 equals 17.28 MeV end cell end table

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