Maths-
General
Easy

Question

The coordinate A=(0,2) lies on a straight line. The gradient of the line is 5 . Using this information, state the equation of the straight line.

hintHint:

We are given the slope of a line and a point which lies on the straight line. To find the equation of the line, we use the point slope form of the equation which is given by y - b = m(x - a), where m is the slope and (a, b) is the point lying on the plane. We simplify this equation and bring it to the general form which is ax + by + c = 0

The correct answer is: 5x - y + 2 = 0


    Step by step solution:
    Given,
    Slope/ Gradient of the line (m) = 5
    Let (a, b) denote the point A lying on the plane.

    Then (a, b) = (0, 2)
    We know that, the equation of a line with slope m and passing through the point (a, b) is given by

    y - b = m(x - a)
    Putting the values of m and (a, b) in the above equation, we get

    y - 2 = 5(x - 0)
    Simplifying, we have

    y - 2 = 5x
    Taking all the terms on one side and rewriting the above equation, we have

    5x - y + 2 = 0
    This is the required equation of the line.
     

    The student needs to remember all the different forms of equation of a line and what each term and notation signifies in the equation.
    Other forms of the equation of a line are, slope intercept form, axis intercept form, normal form, etc.

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