Chemistry-
General
Easy

Question

The enthalpy of vapourisation of liquid water using the data :
straight H subscript 2 left parenthesis straight g right parenthesis plus 1 divided by 2 straight O subscript 2 left parenthesis straight g right parenthesis not stretchy rightwards arrow straight H subscript 2 straight O left parenthesis ell right parenthesis semicolon ΔH equals negative 285.77 KJ mol to the power of negative 1 end exponent
straight H subscript 2 left parenthesis straight g right parenthesis plus 1 divided by 2 straight O subscript 2 left parenthesis straight g right parenthesis not stretchy rightwards arrow straight H subscript 2 straight O left parenthesis straight g right parenthesis semicolon ΔH equals negative 241.84 KJ mol to the power of negative 1 end exponent

  1. plus 43.93 KJmol to the power of negative 1 end exponent
  2. negative 43.93 KJ mol to the power of negative 1 end exponent
  3. plus 527.61 KJmol to the power of negative 1 end exponent
  4. negative 527.61 KJmol to the power of negative 1 end exponent

The correct answer is: plus 43.93 KJmol to the power of negative 1 end exponent

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The conversion A to B is carried out by the following path :
Given colon capital delta S subscript left parenthesis A rightwards arrow C right parenthesis end subscript equals 50 e.u.,capital delta S subscript left parenthesis C rightwards arrow D right parenthesis end subscript equals 30
e.u.,capital delta S subscript left parenthesis B rightwards arrow D right parenthesis end subscript equals 20 e.u.
Where e.u. is entropy unit then capital delta S subscript left parenthesis A rightwards arrow B right parenthesis end subscript is

The conversion A to B is carried out by the following path :
Given colon capital delta S subscript left parenthesis A rightwards arrow C right parenthesis end subscript equals 50 e.u.,capital delta S subscript left parenthesis C rightwards arrow D right parenthesis end subscript equals 30
e.u.,capital delta S subscript left parenthesis B rightwards arrow D right parenthesis end subscript equals 20 e.u.
Where e.u. is entropy unit then capital delta S subscript left parenthesis A rightwards arrow B right parenthesis end subscript is

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A reversible process is taking place at constant temperature and pressure. Then at equilibrium

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chemistry-General
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For B+Drightwards arrowE+2C, capital delta H will be-

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chemistry-General
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General
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From the following bond energies :
H minus H bond energy : 431.37 text end text k J text end text m o l to the power of negative 1 end exponent
C equals C bond energy : 606.10 text end text k J text end text m o l to the power of negative 1 end exponent
C minus C bond energy : 336.49 text end text k J text end text m o l to the power of negative 1 end exponent
C minus H bond energy : 410.50 text end text k J text end text m o l to the power of negative 1 end exponent
Enthalpy for the reaction,

wilbe:

From the following bond energies :
H minus H bond energy : 431.37 text end text k J text end text m o l to the power of negative 1 end exponent
C equals C bond energy : 606.10 text end text k J text end text m o l to the power of negative 1 end exponent
C minus C bond energy : 336.49 text end text k J text end text m o l to the power of negative 1 end exponent
C minus H bond energy : 410.50 text end text k J text end text m o l to the power of negative 1 end exponent
Enthalpy for the reaction,

wilbe:

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For a phase change 

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The heat change during the reaction 24 gC and 128 gS following the change C plus S subscript 2 end subscript rightwards arrow C S subscript 2 end subscript semicolon capital delta H equals 22 text end text K cal

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In which reaction ΔS is positive -

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The heat of combustion of ethanol determined in a bomb calorimeter is -670.48 K. Cals mole-1 at 25°C. What is capital delta H at 25°C for the reaction-

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The binding energies per nucleon of Li to the power of 7 and He to the power of 4 are 5.6 MeV and 7.06 MeV respectively, then the energy of the reaction L i to the power of 7 plus p equals 2 open square brackets 2 to the power of H e to the power of 4 end exponent close square brackets  will be

The binding energies per nucleon of Li to the power of 7 and He to the power of 4 are 5.6 MeV and 7.06 MeV respectively, then the energy of the reaction L i to the power of 7 plus p equals 2 open square brackets 2 to the power of H e to the power of 4 end exponent close square brackets  will be

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Which of the following is true for a sample of isotope containing straight U to the power of 235 and straight U to the power of 238

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Statement 2: The whole mass of the atom is considered in the nucleus

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Statement 1: Hydrogen atom consists of only one electron but its emission spectrum has many lines

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