Question
The length of a rod is 4x + 5y- 3z cm and the length of another is 6x- 3y + z cm. By
How much is the second rod longer than the first?
Hint:
- Subtraction of polynomials.
○ Always take like terms together while performing subtraction.
○ In addition to polynomials only terms with the same coefficient are subtracted.
The correct answer is: Hence, the second rod is 2x - 8y + 4z cm longer than the first.
Answer:
- Step by step explanation:
○ Given:
length of a rod = 4x + 5y- 3z cm
length of another rod = 6x- 3y + z cm.
○ Step 1:
○ Subtract lengths of both rods.
(6x- 3y + z) - (4x + 5y- 3z)
6x- 3y + z - 4x - 5y + 3z
(6x-4x) - (3y + 5y) + (z + 3z)
(2x) - (8y) + (4z)
2x - 8y + 4z
- Final Answer:
Hence, the second rod is 2x - 8y + 4z cm longer than the first.
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