Maths-
General
Easy

Question


The line graph above shows the average price of one metric ton of oranges, in dollars, for each of seven months in 2014.
In 2014, the average price of one metric ton of
oranges decreased by 2.36% from January (not
shown) to February. Which of the following is closest
to the price of one metric ton of oranges in
January 2014?

  1. 700
  2. 770
  3. 790
  4. 830

hintHint:

Hint:
The graph gives the average price on one metric ton of oranges for
seven months starting from February. We need find the average
price on one metric ton of oranges for January. We are given a
condition in the question and we use it to find the required value
The term ‘ decreased by 2.36%’ means that the average price
reduced in February by 2.36% of the average price in January.

The correct answer is: 790


    Let the average price of one metric ton of oranges in January be  x$.
    From the graph, we have
    Approximate average price of one metric ton of oranges in February=776$
    It is given that the average price of one metric ton of oranges decreased by 2.36% from January to February.
    So, according to the given condition
    x minus 2.36 straight percent sign text  of  end text x equals 776
    Rewriting the above equation, we have
    x minus fraction numerator 2.36 over denominator 100 end fraction x equals 776
    Multiplying throughout with 100, we get
    100 x minus 2.36 x equals 77600
    Simplifying, we have
    97.64 x equals 77600
    Dividing both sides by 96.64 , we have
    x equals fraction numerator 77600 over denominator 97.64 end fraction equals 794.76
    Thus, we get
    Approximate average price of one metric ton of oranges in January=794.76 $
    From the options, it can be seen that 790 is closest to 794.76
    Thus, the correct option is C)

    Note:
    Interpreting the condition given in the question and forming the equation is a crucial part of this problem.
    To find the closest value to 794.76, we need to find the difference between 794.76 and the numbers given in the options, and choose the minimum one to get the closest value

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