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Question

The parallel sides of a trapezium are 20cm and 10cm. Its non parallel sides are both equal. Each being 13cm. Find the area of the trapezium ?

hintHint:

Draw the parallel line from B parallel to AD which cuts the CD at E .
We get a triangle and parallelogram. we find the area of triangle in both heron's
method and using formula area = ½ b × h and equating we get height h
Now , find the area of Trapezium =  ½ height × (sum of lengths of parallel sides).

The correct answer is: 180 cm2


    Ans :- 180 cm2.
    Explanation :-
    Step 1:- Given lengths of parallel sides is 10 and 20 cm .
    Length of non parallel sides is 13 and 13 cm
    We get a triangle and parallelogram ABED
    we get BE = 13 cm ; DE = 10 cm (opposites sides of parallelogram )
    CE = CD-DE = 20 - 10 = 10 cm .


    Step 2:- Equate the areas and find value of height h
    5 h equals 60 not stretchy rightwards double arrow h equals 60 over 5 equals 12 cm
    Step 3:-Find the area of trapezium
    text  Areaoftrapezium  end text equals 1 half cross times left parenthesis text  height  end text right parenthesis cross times left parenthesis text  sumoflengthsofparallelsides  end text right parenthesis
    text  Area of trapezium  end text equals 1 half left parenthesis 12 right parenthesis left parenthesis 10 plus 20 right parenthesis equals 6 cross times 30 equals 180 cm squared
    Therefore, Area of trapezium ABCD  = 180 cm2.

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