Question
The ratio of the lengths of the parallel sides of a trapezium is 3:2. The shortest distance between them is 15cm. If the area of the trapezium is 450 sq. cm. Find the sum of the lengths of the parallel sides ?
Hint:
let the length of parallel sides be x and y (x>y).Given ratio of x:y = 3:2
Substitute the equation in the formula area of trapezium = ½ × (height)(sum of lengths
of parallel side) and equate to find x
The correct answer is: 60 cm
Ans :- 60 cm
Explanation :-
Step 1:- Find the equation between x and y and find the sum of lengths of parallel sides in terms of y.
let the length of parallel sides be x and y (x>y).
Given ratio of x:y = 3:2
Sum of lengths of parallel sides =
Step 2:-substitute the values in the area formula find x
Given area of trapezium = 450 sq.cm
Altitude (or) height = 15 cm
area of trapezium = ½ × (height)(sum of lengths of parallel side)
We know Sum of lengths of parallel sides =
So, Sum of lengths of parallel sides = 60 cm.
Therefore, Sum of lengths of parallel sides is 60 cm.
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