Maths-
General
Easy

Question

The parallel sides of a trapezium are 30cm and 40cm and the other sides are 24cm and 26cm. Find its area?

hintHint:

Draw the parallel line from C parallel to AD which cuts the AB at E .
We get a triangle and parallelogram. we find the area of triangle in both heron's
method and using formula area = ½ b × h and equating we get height h
Now , find the area of Trapezium =  ½ height × (sum of lengths of parallel sides).

The correct answer is: 840 cm2


    Ans :- 840 cm2.
    Explanation :-
    Step 1:- Given lengths of parallel sides is 30  and 40 cm .
    Length of non parallel sides is 24 and 26 cm
    We get a triangle and parallelogram ABED
    we get CE = 24 cm ; AE = 30 cm (opposites sides of parallelogram )
    BE = BA-AE = 40 - 30 = 10 cm .


    Step 2:- Equate the areas and find value of height h
    bold 5 bold italic h equals 120 not stretchy rightwards double arrow bold italic h equals 24 bold cm
    Step 3:-Find the area of trapezium
    text  Areaoftrapezium  end text equals 1 half cross times left parenthesis text  height  end text right parenthesis cross times left parenthesis text  sumoflengthsofparallelsides  end text right parenthesis
    text  Area of trapezium  end text equals 1 half left parenthesis 24 right parenthesis left parenthesis 30 plus 40 right parenthesis equals 12 cross times 70 equals 840 cm squared
    Therefore, Area of trapezium ABCD  =  840 cm2.

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