Maths-
General
Easy
Question
The total numbers of integral solutions for (x,y,z) such that xyz = 24 is
- 36
- 90
- 96
- 120
The correct answer is: 120
24 can be broken as (1, 1, 24),(1, 2, 12),(1, 3, 8),(1, 4, 6),(2, 3, 4) & (2, 2, 6)
All sets in which each no. is diff = 3C2. 3! + 3!= 24
in which two nos. are same = 
total no. of possible sets= 24 × 4 + 12 × 2 = 120
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