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Physics-

General

Easy

Question

Two capacitors C₁ and C₂ are charged to same potential V, but with opposite polarity as shown in the figure. The switch S₁ and S₂ are then closed

p.d. across two capacitors are same and is given by $\frac{(C_{1} - C_{2}) V}{(C_{1} + C_{2})}$
p.d. across two capacitors are same and is given by $\frac{C_{1} V}{C_{1} + C_{2}}$
ratio of final energy to initial energy of the system is given by $\frac{{(C_{1} - C_{2})}^{2}}{{(C_{1} + C_{2})}^{2}}$
ratio of final energy to initial energy of the system is given by $\frac{{(C_{1})}^{2}}{{(C_{1} + C_{2})}^{2}}$

The correct answer is: p.d. across two capacitors are same and is given by $fraction numerator left parenthesis C subscript 1 minus C subscript 2 right parenthesis V over denominator left parenthesis C subscript 1 plus C subscript 2 right parenthesis end fraction$

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