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Physics

General

Easy

Question

What is the equation for a damped oscillator, where k and b are constants and is x displacement.

$\frac{{md}^{2} x}{{dt}^{2}} = kx + \frac{bd x}{dt} = 0$
$\frac{{md}^{2} x}{{dt}^{2}} XkX = \frac{bd x}{dt}$
$m \frac{d^{2} x}{{dt}^{2}} = kx + \frac{bd x}{dt}$
$\frac{{md}^{2} x}{{dt}^{2}} - kx = b \frac{d x}{dt}$

The correct answer is: $fraction numerator md squared x over denominator dt squared end fraction equals kx plus fraction numerator bd x over denominator dt end fraction equals 0$

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