Maths-
General
Easy

Question

Write the equation in slope-intercept form of the line that passes through the points (-2, -1) and (0, -5).

hintHint:

The slope-intercept form of a line is y = mx + c, where m Is the slope of the line and c is the y- intercept. You obtain the value of y-intercept when you take x = 0.
We are asked to find the equation of the line passing through the given points in the slope intercept form.

The correct answer is: Y = - 2x - 5


    Step 1 of 2:
    The given points are: (-2, -1) and (0, -5). The slope intercept form of a line is: y = mx + c.
    Find the slope of the line using the given points:
    m equals fraction numerator y subscript 2 minus y subscript 1 over denominator x subscript 2 minus x subscript 1 end fraction
    m equals fraction numerator negative 5 minus left parenthesis negative 1 right parenthesis over denominator 0 minus left parenthesis negative 2 right parenthesis end fraction
    m equals fraction numerator negative 5 plus 1 over denominator 0 plus 2 end fraction
    m equals fraction numerator negative 4 over denominator 2 end fraction
    m equals negative 2
    Thus, the equation of the line changes to y = - 2x + c.
    Step 2 of 2:
    The y-intercept is the value for y when x = 0.
    Here, when x = 0, the value of y = - 5. Thus, the y-intercept is c = - 5.
    Hence, the equation of the line is:
    Y = - 2x - 5

    If the slope of the line is to be examined and the given point is also the
    ¶y-intercept, you can apply the slope-intercept formula, y = mx + b. (0, b). The y value of the
    ¶y-intercept point is represented by the symbol b in the formula. If we know the slope between two points on a line, we can use that information to solve for the y-intercept in the slope-intercept equation y=mx+b. Here, we'll develop an equation for the line that connects the points (-1, 6) and (5,-4)

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