General
General
Easy
Question
Write the equation of a line perpendicular to y = 3x - 8 and that passes through the point (-3, -9)
- y + 9 = (x + 3)
- y - 9 = (x - 3)
- y + 9 = -3(x + 3)
- y - 9 = 3(x - 3)
Hint:
We are given an equation of line. We have to find the equation of line that is perpendicular to the given line and passing through point (-3,-9). We will use the properties of perpendicular lines to solve the question.
The correct answer is: y + 9 = (x + 3)
The given equation of line is y = 3x - 8
We have to find line perpendicular to this line.
Perpendicular lines have a slope that are negative reciprocals each other.
To find the slope of the given line, we will compare the equation with slope-intercept form. The slope-intercept form of a line is y = mx + c. Here m is the slope of the line and c is the y-intercept.
Comparing the given equation of line with slope-intercept form we get,
m = 3
So, our new line will have slope
Now, we have a point through which line is passing and slope. We will use slope-point form to find the perpendicular line.
Slope-point form is (y – y1) = m1(x – x1). Here y1 and X1 are the points through which line is passing. (x1,y1) ≡ (-3, -9)
Substituting all the values
Therefore, the equation of line perpendicular to given line and passing through point (-3,-9) is .
For such questions, we should know different formulas required to find lines. We should also know the concept of slope of different lines.
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