Chemistry
Grade-9
Easy
Question
0.1g if carbon dioxide occupies a volume of 320cc at certain conditions. Under similar condition 0.2g of dioxide of element ‘X’ occupies 440cc. Calculate the atomic weight ‘X’.
- 34
- 39
- 32
- 38
The correct answer is: 32
According to the ideal gas equation, PV = nRT. Here,
V1 = 320 cc = 0.32 L
m of CO2 = 12 + 16 x 2 = 12 + 32 = 44
n1 = w/m = 0.1/44 gm = 0.0022
V2 = 440 cc = 0.44 L
Now, n2 = w/m
Hence, x = 34
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