Chemistry
Grade-9
Easy
Question
3gm of an impure sample of sodium sulfate dissolved in water was treated with an excess of BaCl2 solution when 1.74g of BaSO4 were obtained as dry precipitate. Calculate the percentage purity of the sample.
- 35.33%
- 45%
- 45.5%
- 50%
Hint:
142 g of sodium sulfate gives 233g of barium sulphate.
The correct answer is: 35.33%
Na2SO4 + BaCl2 
2NaCl + BaSO4
142 g of sodium sulfate gives 233g of barium sulphate.
Amount of sodium sulfate that gives 1.74g of barium sulphate is 1.06g
Purity of sample = (1.06
3)
100% = 35.33%
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