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Chemistry-

General

Easy

Question

In nuclear reaction, $blank subscript 3 end subscript superscript 7 end superscript L i plus blank subscript 1 end subscript superscript 1 end superscript H rightwards arrow 2 blank subscript 2 end subscript superscript 4 end superscript H e$ The mass loss is nearly 0.02 amu. Hence, the energy released (in units of million kcal/mol) in the process is approximately

430
220
120
50

The correct answer is: 430

Mass defect $equals 0.02 blank a m u$
$equals fraction numerator 0.02 over denominator N subscript 0 end subscript end fraction g blank a t o m to the power of negative 1 end exponent equals fraction numerator 0.02 over denominator N subscript 0 end subscript end fraction cross times N subscript 0 end subscript blank g blank m o l to the power of negative 1 end exponent$
$equals 0.02 blank g blank m o l to the power of negative 1 end exponent$
$E equals m c to the power of 2 end exponent equals 0.02 cross times 9 cross times 10 to the power of 20 end exponent e r g blank m o l to the power of negative 1 end exponent$
$equals fraction numerator 0.02 cross times 9 cross times 10 to the power of 20 end exponent cross times 0.002 over denominator 8.314 cross times 10 to the power of 7 end exponent cross times 10 to the power of 6 end exponent end fraction m i l l i o n blank k c a l blank m o l to the power of negative 1 end exponent$
$almost equal to 430 blank open parentheses fraction numerator 1 blank m i l l i o n equals 10 to the power of 6 end exponent over denominator 8.314 cross times 10 to the power of 7 end exponent e r g equals 0.002 blank k c a l end fraction close parentheses$

Related Questions to study

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There are $0.618 blank mu g blank$ of $blank to the power of 206 end exponent P b$ and $0.238 blank mu g blank$ of $blank to the power of 238 end exponent U$ in a rock. If $T subscript 50 end subscript$ of $blank to the power of 238 end exponent U$ is $1.5 cross times 10 to the power of 9 end exponent y r comma$ age of the rock is

Chemistry-General

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