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Chemistry-

General

Easy

Question

In the following reaction, .

The major product obtained is :

The correct answer is:

Related Questions to study

For the following reaction,

product [A] is:

For the following reaction,

product [A] is:

Chemistry-General

When 2-chloro-2-methylbutane is heated with alcoholic KOH, the possible product/s is/are:
i) $open parentheses C H subscript 3 end subscript close parentheses subscript 2 end subscript C equals C H C H subscript 3 end subscript$
ii) $H subscript 2 end subscript C equals stack C with bar on top open parentheses C H subscript 3 end subscript close parentheses stack C with bar on top H subscript 2 end subscript C H subscript 3 end subscript$
iii) $open parentheses C H subscript 3 end subscript close parentheses subscript 2 end subscript C H C H equals C H subscript 2 end subscript$

When 2-chloro-2-methylbutane is heated with alcoholic KOH, the possible product/s is/are:
i) $open parentheses C H subscript 3 end subscript close parentheses subscript 2 end subscript C equals C H C H subscript 3 end subscript$
ii) $H subscript 2 end subscript C equals stack C with bar on top open parentheses C H subscript 3 end subscript close parentheses stack C with bar on top H subscript 2 end subscript C H subscript 3 end subscript$
iii) $open parentheses C H subscript 3 end subscript close parentheses subscript 2 end subscript C H C H equals C H subscript 2 end subscript$

Chemistry-General

(A) predominantly is:

(A) predominantly is:

Chemistry-General

parallel

Ethyl chloride on reduction with $L i A l H subscript 4 end subscript$ gives compound , X' as an important product. 'X' on chlorination with one mole of Cl₂ in the presence of light at ordinary temperature gives' Y'. What is 'Y' ?

Ethyl chloride on reduction with $L i A l H subscript 4 end subscript$ gives compound , X' as an important product. 'X' on chlorination with one mole of Cl₂ in the presence of light at ordinary temperature gives' Y'. What is 'Y' ?

Chemistry-General

(X) is:

(X) is:

Chemistry-General

Which can undergo haloform reaction?

Which can undergo haloform reaction?

Chemistry-General

parallel

when treated with two equivalents of sodium in dry ether gives:

when treated with two equivalents of sodium in dry ether gives:

Chemistry-General

the major product formed in the following reaction,
is:

the major product formed in the following reaction,
is:

Chemistry-General

Which of the following is liquid at room .temperature?

Which of the following is liquid at room .temperature?

Chemistry-General

parallel

$stack L t with x rightwards arrow 1 below open square brackets fraction numerator x to the power of 3 end exponent plus 2 x to the power of 2 end exponent plus x plus 1 over denominator x to the power of 2 end exponent plus 2 x plus 3 end fraction close square brackets to the power of fraction numerator 1 minus cos invisible function application left parenthesis x minus 1 right parenthesis over denominator left parenthesis x minus 1 right parenthesis to the power of 2 end exponent end fraction end exponent$ is

$stack L t with x rightwards arrow 1 below open square brackets fraction numerator x to the power of 3 end exponent plus 2 x to the power of 2 end exponent plus x plus 1 over denominator x to the power of 2 end exponent plus 2 x plus 3 end fraction close square brackets to the power of fraction numerator 1 minus cos invisible function application left parenthesis x minus 1 right parenthesis over denominator left parenthesis x minus 1 right parenthesis to the power of 2 end exponent end fraction end exponent$ is

$stack L t with x rightwards arrow 2 below open parentheses fraction numerator x to the power of 3 end exponent minus 4 x over denominator x to the power of 3 end exponent minus 8 end fraction close parentheses to the power of negative 1 end exponent minus open parentheses fraction numerator x plus square root of 2 x end root over denominator x minus 2 end fraction minus fraction numerator square root of 2 over denominator square root of x minus square root of 2 end fraction close parentheses to the power of negative 1 end exponent$ is

$stack L t with x rightwards arrow 2 below open parentheses fraction numerator x to the power of 3 end exponent minus 4 x over denominator x to the power of 3 end exponent minus 8 end fraction close parentheses to the power of negative 1 end exponent minus open parentheses fraction numerator x plus square root of 2 x end root over denominator x minus 2 end fraction minus fraction numerator square root of 2 over denominator square root of x minus square root of 2 end fraction close parentheses to the power of negative 1 end exponent$ is

$stack l i m with x rightwards arrow infinity below fraction numerator left parenthesis x plus 1 right parenthesis to the power of 10 end exponent plus left parenthesis x plus 2 right parenthesis to the power of 10 end exponent plus... plus left parenthesis x plus 100 right parenthesis to the power of 10 end exponent over denominator x to the power of 10 end exponent plus 1 0 to the power of 10 end exponent end fraction$ is equal to

$stack l i m with x rightwards arrow infinity below fraction numerator left parenthesis x plus 1 right parenthesis to the power of 10 end exponent plus left parenthesis x plus 2 right parenthesis to the power of 10 end exponent plus... plus left parenthesis x plus 100 right parenthesis to the power of 10 end exponent over denominator x to the power of 10 end exponent plus 1 0 to the power of 10 end exponent end fraction$ is equal to

parallel

Let $f left parenthesis x right parenthesis equals fraction numerator log invisible function application left parenthesis 1 plus x plus x to the power of 2 end exponent right parenthesis plus log invisible function application left parenthesis 1 minus x plus x to the power of 2 end exponent right parenthesis over denominator sec invisible function application x minus cos invisible function application x end fraction$ , x $not equal to$ 1. The value of f(0) so that f is continuous at x = 0 is

Let $f left parenthesis x right parenthesis equals fraction numerator log invisible function application left parenthesis 1 plus x plus x to the power of 2 end exponent right parenthesis plus log invisible function application left parenthesis 1 minus x plus x to the power of 2 end exponent right parenthesis over denominator sec invisible function application x minus cos invisible function application x end fraction$ , x $not equal to$ 1. The value of f(0) so that f is continuous at x = 0 is

$stack l i m with x rightwards arrow 1 below fraction numerator left parenthesis 1 minus x right parenthesis left parenthesis 1 minus x to the power of 2 end exponent right parenthesis... left parenthesis 1 minus x to the power of 2 n end exponent right parenthesis over denominator left square bracket left parenthesis 1 minus x right parenthesis left parenthesis 1 minus x to the power of 2 end exponent right parenthesis... left parenthesis 1 minus x to the power of n end exponent right parenthesis right square bracket to the power of 2 end exponent end fraction$ is

$stack l i m with x rightwards arrow 1 below fraction numerator left parenthesis 1 minus x right parenthesis left parenthesis 1 minus x to the power of 2 end exponent right parenthesis... left parenthesis 1 minus x to the power of 2 n end exponent right parenthesis over denominator left square bracket left parenthesis 1 minus x right parenthesis left parenthesis 1 minus x to the power of 2 end exponent right parenthesis... left parenthesis 1 minus x to the power of n end exponent right parenthesis right square bracket to the power of 2 end exponent end fraction$ is

A function f(x) is defined as below $f left parenthesis x right parenthesis equals fraction numerator cos invisible function application left parenthesis sin invisible function application x right parenthesis minus cos invisible function application x over denominator x to the power of 2 end exponent end fraction comma x not equal to 0$ , f(0) = a, f(x) is continuous at x = 0 if a equals

A function f(x) is defined as below $f left parenthesis x right parenthesis equals fraction numerator cos invisible function application left parenthesis sin invisible function application x right parenthesis minus cos invisible function application x over denominator x to the power of 2 end exponent end fraction comma x not equal to 0$ , f(0) = a, f(x) is continuous at x = 0 if a equals

parallel

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