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Chemistry-

General

Easy

Question

In the group the carbonyl carbon is joined to other atoms by:

two sigma and one pi bond
three sigma and one pi bond
two sigma and two pi bonds
three sigma and two pi bonds

The correct answer is: three sigma and one pi bond

Related Questions to study

Compare the integers.,> , < or =
-252 + 312 - 400 -212 - 452 + 300

Compare the integers.,> , < or =
-252 + 312 - 400 -212 - 452 + 300

$text If a end text equals cos squared invisible function application straight A plus ysin squared space straight A space then space left parenthesis straight x minus straight a right parenthesis left parenthesis straight y minus straight a right parenthesis plus left parenthesis straight x minus straight y right parenthesis squared sin squared space Acos squared space straight A equals$

$text If a end text equals cos squared invisible function application straight A plus ysin squared space straight A space then space left parenthesis straight x minus straight a right parenthesis left parenthesis straight y minus straight a right parenthesis plus left parenthesis straight x minus straight y right parenthesis squared sin squared space Acos squared space straight A equals$

$text If end text fraction numerator cos squared begin display style text end text end style theta over denominator a end fraction equals fraction numerator sin squared begin display style space end style theta over denominator b end fraction text then end text fraction numerator cos to the power of 4 begin display style text end text end style theta over denominator a end fraction plus fraction numerator sin to the power of 4 begin display style space end style theta over denominator b end fraction equals$

$text If end text fraction numerator cos squared begin display style text end text end style theta over denominator a end fraction equals fraction numerator sin squared begin display style space end style theta over denominator b end fraction text then end text fraction numerator cos to the power of 4 begin display style text end text end style theta over denominator a end fraction plus fraction numerator sin to the power of 4 begin display style space end style theta over denominator b end fraction equals$

parallel

$tan space A equals a tan space B comma sin space A equals b sin space B not stretchy rightwards arrow fraction numerator a to the power of negative 1 end exponent 1 over denominator a squared equals 1 end fraction equals$

$tan space A equals a tan space B comma sin space A equals b sin space B not stretchy rightwards arrow fraction numerator a to the power of negative 1 end exponent 1 over denominator a squared equals 1 end fraction equals$

$text a sec end text theta plus b tan space theta equals 1 comma text a sec end text theta minus b tan space theta equals 5 not stretchy rightwards double arrow a squared open parentheses b squared plus 4 close parentheses equals$

$text a sec end text theta plus b tan space theta equals 1 comma text a sec end text theta minus b tan space theta equals 5 not stretchy rightwards double arrow a squared open parentheses b squared plus 4 close parentheses equals$

if $x equals acos squared space theta sin space theta$ and $y equals asin squared space theta cos space theta$ then $fraction numerator open parentheses x squared plus y squared close parentheses to the power of 4 over denominator x squared y squared end fraction equals$

if $x equals acos squared space theta sin space theta$ and $y equals asin squared space theta cos space theta$ then $fraction numerator open parentheses x squared plus y squared close parentheses to the power of 4 over denominator x squared y squared end fraction equals$

parallel

$cos squared space 5 to the power of ring operator plus cos squared space 10 to the power of minus plus cos squared space 15 to the power of ring operator plus midline horizontal ellipsis plus cos squared space 360 to the power of ring operator equals$

$cos squared space 5 to the power of ring operator plus cos squared space 10 to the power of minus plus cos squared space 15 to the power of ring operator plus midline horizontal ellipsis plus cos squared space 360 to the power of ring operator equals$

If $1 plus sin space x plus sin squared space x plus$ to $straight infinity equals 4 plus 2 square root of 3 comma 0 less than x less than pi$ and $x not equal to 11 over 2 text then end text x equals$

If $1 plus sin space x plus sin squared space x plus$ to $straight infinity equals 4 plus 2 square root of 3 comma 0 less than x less than pi$ and $x not equal to 11 over 2 text then end text x equals$

If sin $theta plus$ cos $theta equals$ m and sec $theta plus$ cosec $theta equals$ n, then $n left parenthesis m plus 1 right parenthesis left parenthesis m minus 1 right parenthesis equals$

If sin $theta plus$ cos $theta equals$ m and sec $theta plus$ cosec $theta equals$ n, then $n left parenthesis m plus 1 right parenthesis left parenthesis m minus 1 right parenthesis equals$

parallel

if $square root of fraction numerator 1 minus sin space A over denominator 1 plus sin space A end fraction end root equals$ sec A-tan A then lies in the quadrants

if $square root of fraction numerator 1 minus sin space A over denominator 1 plus sin space A end fraction end root equals$ sec A-tan A then lies in the quadrants

cosec $straight A equals 4 straight p plus fraction numerator 1 over denominator 16 straight p end fraction not stretchy rightwards double arrow$ cosec A +cot A=

cosec $straight A equals 4 straight p plus fraction numerator 1 over denominator 16 straight p end fraction not stretchy rightwards double arrow$ cosec A +cot A=

The total amount of fee collection for 21 students is $31500. How much was paid by each student.

The total amount of fee collection for 21 students is $31500. How much was paid by each student.

parallel

is a

is a

Chemistry-General

In the reaction,

In the reaction,

Chemistry-General

In the given action,

the product [X] will be:

In the given action,

the product [X] will be:

Chemistry-General

parallel

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