Question
Isomers are possible for the molecular formula
- CH4O
- C2H3Cl
- C2H3Cl3
- CH5N
The correct answer is: C2H3Cl3
Related Questions to study
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To solve a trigonometric inequation of the type sin x ≥ a where |a| ≤ 1, we take a hill of length 2 in the sine curve and write the solution within that hill. For the general solution, we add 2n. For instance, to solve , we take the hill over which solution is The general solution is , n is any integer. Again to solve an inequation of the type sin x ≤ a, where |a| ≤ 1, we take a hollow of length 2 in the sine curve. (since on a hill, sinx ≤ a is satisfied over two intervals). Similarly cos x ≥ a or cosx ≤a, |a| ≤ 1 are solved.
Solution to the inequation must be
To solve a trigonometric inequation of the type sin x ≥ a where |a| ≤ 1, we take a hill of length 2 in the sine curve and write the solution within that hill. For the general solution, we add 2n. For instance, to solve , we take the hill over which solution is The general solution is , n is any integer. Again to solve an inequation of the type sin x ≤ a, where |a| ≤ 1, we take a hollow of length 2 in the sine curve. (since on a hill, sinx ≤ a is satisfied over two intervals). Similarly cos x ≥ a or cosx ≤a, |a| ≤ 1 are solved.
Solution to the inequation must be
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