Maths-
General
Easy

Question

If A plus B plus C equals pi comma then tan squared invisible function application A over 2 plus tan squared invisible function application B over 2 plus tan squared invisible function application C over 2 is always

  1. less or equal than 1    
  2. greater or equal than 1    
  3. = 0    
  4. = 1    

The correct answer is: greater or equal than 1


    tan invisible function application open parentheses fraction numerator A over denominator 2 end fraction plus fraction numerator B over denominator 2 end fraction plus fraction numerator C over denominator 2 end fraction close parentheses equals fraction numerator S subscript 1 end subscript minus S subscript 3 end subscript over denominator 1 minus S subscript 2 end subscript end fraction equals tan invisible function application fraction numerator pi over denominator 2 end fraction equals infinity
    therefore S subscript 2 end subscript equals 1 or x y plus y z plus z x equals 1, where x equals tan invisible function application fraction numerator A over denominator 2 end fractionetc.
    Now left parenthesis x minus y right parenthesis to the power of 2 end exponent plus left parenthesis y minus z right parenthesis to the power of 2 end exponent plus left parenthesis z minus x right parenthesis to the power of 2 end exponent greater or equal than 0
    or 2 sum x to the power of 2 end exponent minus 2 sum x y greater or equal than 0 rightwards double arrow sum x to the power of 2 end exponent greater or equal than 1. left curly bracket because sum x y equals 1 right curly bracket

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