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Chemistry-

General

Easy

Question

Which of the following will be obtained by keeping ether in contact with air for a long time?

$C_{2} H_{5} - O - C H ({C H}_{3}) - O - O H$
$C_{2} H_{5} - O - {C H}_{3} O H$
$C_{2} H_{5} - O - C_{2} H_{5} O H$
${C H}_{3} - O - C H ({C H}_{3}) - O - O H$

The correct answer is: $C subscript 2 end subscript H subscript 5 end subscript minus O minus C H open parentheses C H subscript 3 end subscript close parentheses minus O minus O H$

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$I n blank a blank capital delta A B C blank i f blank 2 R plus r equals r subscript 1 end subscript comma blank t h e n$

$I n blank a blank capital delta A B C blank i f blank 2 R plus r equals r subscript 1 end subscript comma blank t h e n$

The resistance of 1 A ammeter is $0.018 capital omega$ . To convert it into 10 A ammeter, the shunt resistance required will be

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$I n blank a blank t r i a n g l e blank A B C comma square root of a plus square root of b minus square root of c blank i s$

$I n blank a blank t r i a n g l e blank A B C comma square root of a plus square root of b minus square root of c blank i s$

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$l n invisible function application a capital delta A B C blank i f blank a to the power of 2 end exponent s i n invisible function application left parenthesis B minus C right parenthesis plus b to the power of 2 end exponent s i n invisible function application left parenthesis C minus A right parenthesis plus c to the power of 2 end exponent s i n invisible function application left parenthesis A minus B right parenthesis equals 0 blank comma blank t h e n text triangle is end text$

$l n invisible function application a capital delta A B C blank i f blank a to the power of 2 end exponent s i n invisible function application left parenthesis B minus C right parenthesis plus b to the power of 2 end exponent s i n invisible function application left parenthesis C minus A right parenthesis plus c to the power of 2 end exponent s i n invisible function application left parenthesis A minus B right parenthesis equals 0 blank comma blank t h e n text triangle is end text$

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$I f blank x comma y comma z$ are perpendicular drawn from the vertices of a triangle having a, band c, then $fraction numerator b x over denominator c end fraction plus fraction numerator c y over denominator a end fraction plus fraction numerator a z over denominator b end fraction$ is equal to

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are more acidic than water:
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Alcohols are ,acidic in nature because hydrogen is attached to oxygen which is an electronegative element. Alcohol is weaker acid than water because $O H to the power of minus end exponent$ ion is more stable than $R minus O to the power of minus end exponent$ ion $R minus 0 to the power of minus end exponent$ is less stable, due to +I effect of the alkyl group., Acidity of alcohols increases with increase:' in ' the stability of acid anion.

Some alcohols . like $C H subscript 3 end subscript minus O H comma C F subscript 3 end subscript minus C H subscript 2 end subscript minus O H$ , $blank open parentheses C F subscript 3 end subscript close parentheses subscript 3 end subscript C minus O H$
are more acidic than water:
Which of the following will react fastest with sodium?

Chemistry-General

In meter bridge or Wheatstone bridge for measurement of resistance, the known and the unknown resistances are interchanged. The error so removed is

In meter bridge or Wheatstone bridge for measurement of resistance, the known and the unknown resistances are interchanged. The error so removed is

Physics-General

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