Question
5x + 2y = -13
-x – 2y = 1
- 2, 5
- 5, 8
- -3, 1
- -4, -1
Hint:
An equation has a constant, variable and an equal to sign. It has two sides LHS and RHS. A linear equation is equation in which the highest degree is 1. Here, we have to find the value of unknown value, by operating both sides with the same number so that the equation will be balanced.
The correct answer is: -3, 1
In the question the given equations are
5x + 2y = -13 ....................(1)
-x – 2y = 1 ...................(2)
Step 1: Add eq. 1 with eq. 2.
5x+2y=-13
-x-2y=1
------------------
4x =-12
So, the value of x is -3.
Step 2: Put the value of x in eq. 2.
Put the value of x= -3 in eq. 2.
-x-2y=1
-(-3)-2y=1
3-2y=1
-2y=1-3
-2y=-2
So, the value of y is 1.
Thus, the solutions are -3,1.
Therefore, the correct option is c, i.e., -3,1.
We can solve the equation in two variable using elimination method, substitution method and cross multiplication method. In elimination method we can find the solution of the two variables by cancelling one variable by adding, multiplying or subtracting both the equations from which we will get the value of one variable. After getting the value of one variable we can put the value of that variable in equation and get the value of another variable.
Related Questions to study
x – 2y = 7
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We can solve the equation in two variable using elimination method, substitution method and cross multiplication method. In elimination method we can find the solution of the two variables by cancelling one variable by adding, multiplying or subtracting both the equations from which we will get the value of one variable. After getting the value of one variable we can put the value of that variable in equation and get the value of another variable.
x – 2y = 7
-2x + y = 1
We can solve the equation in two variable using elimination method, substitution method and cross multiplication method. In elimination method we can find the solution of the two variables by cancelling one variable by adding, multiplying or subtracting both the equations from which we will get the value of one variable. After getting the value of one variable we can put the value of that variable in equation and get the value of another variable.
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