Mathematics

Grade10

Easy

Question

Express the function as a piecewise-defined function.
f(x) = -2 IxI

f(x) : {(2x , x ≥ 0) , (-2x , x < 0)}
f(x) : {( $\frac{x}{2}$ , x ≥ 0), (- $\frac{x}{2}$ , x < 0)}
f(x) : {(-2x , x ≥ 0), (2x , x < 0)}
f(x) : {(x , x ≥ 0), (-x , x < 0)}

hint Hint:

A piecewise-defined function is one that is defined not by a single equation, but by two or more. Each equation is valid for some interval.
We simply check the values of f(x) for different values of x and find out the corresponding piecewise-defined function f using function notation.

The correct answer is: f(x) : {(-2x , x ≥ 0), (2x , x < 0)}

Step 1 of 1:
For x = -2, f(x) = -2|-2| = -4
For x = -1, f(x) = -2|-1| = -2
For x = 0, f(x) = 0
For x = 1, f(x) = -2
For x = 2, f(x) = -4
Hence, we have f(x) : {(-2x, x ≥ 0), (2x, x < 0)}
Final Answer:
The right choice is- b. f(x) : {(-2x , x ≥ 0), (2x , x < 0)}

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$f left parenthesis x right parenthesis equals open curly brackets table attributes columnalign left end attributes row cell 100 comma end cell cell 0 less than x less or equal than 4 end cell row cell 95 comma end cell cell 4 less than x less or equal than 8 end cell row cell 90 comma end cell cell 8 less than x less or equal than 12 end cell row cell 95 comma end cell cell 12 less than x less or equal than 16 end cell end table close$ is

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Express the function as a piecewise-defined function.f(x) = -2 IxI

f(x) : {(2x , x ≥ 0) , (-2x , x < 0)}f(x) : {( , x ≥ 0), (- , x < 0)}f(x) : {(-2x , x ≥ 0), (2x , x < 0)}f(x) : {(x , x ≥ 0), (-x , x < 0)}

A piecewise-defined function is one that is defined not by a single equation, but by two or more. Each equation is valid for some interval.We simply check the values of f(x) for different values of x and find out the corresponding piecewise-defined function f using function notation.

The correct answer is: f(x) : {(-2x , x ≥ 0), (2x , x < 0)}

Step 1 of 1:For x = -2, f(x) = -2|-2| = -4For x = -1, f(x) = -2|-1| = -2For x = 0, f(x) = 0For x = 1, f(x) = -2For x = 2, f(x) = -4Hence, we have f(x) : {(-2x, x ≥ 0), (2x, x < 0)}Final Answer:The right choice is- b. f(x) : {(-2x , x ≥ 0), (2x , x < 0)}

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Express the function as a piecewise-defined function.
f(x) = -2 IxI

f(x) : {(2x , x ≥ 0) , (-2x , x < 0)}
f(x) : {( $\frac{x}{2}$ , x ≥ 0), (- $\frac{x}{2}$ , x < 0)}
f(x) : {(-2x , x ≥ 0), (2x , x < 0)}
f(x) : {(x , x ≥ 0), (-x , x < 0)}

A piecewise-defined function is one that is defined not by a single equation, but by two or more. Each equation is valid for some interval.
We simply check the values of f(x) for different values of x and find out the corresponding piecewise-defined function f using function notation.

Step 1 of 1:
For x = -2, f(x) = -2|-2| = -4
For x = -1, f(x) = -2|-1| = -2
For x = 0, f(x) = 0
For x = 1, f(x) = -2
For x = 2, f(x) = -4
Hence, we have f(x) : {(-2x, x ≥ 0), (2x, x < 0)}
Final Answer:
The right choice is- b. f(x) : {(-2x , x ≥ 0), (2x , x < 0)}

Express the function as a piecewise-defined function.
f(x) = 5IxI

Express the function as a piecewise-defined function.
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$open ceil 5.1 close ceil$ =

The value of $vertical line vertical line space x vertical line minus 7 vertical line$ for x = -4 is

The value of $vertical line vertical line space x vertical line minus 7 vertical line$ for x = -4 is

$open ceil negative 2.54 close ceil minus open floor negative 2.54 close floor$ =

$open ceil negative 2.54 close ceil minus open floor negative 2.54 close floor$ =