Question
Find area of the shaded region of this figure.
Hint:
Area of a rectangle= length x breadth
The correct answer is:
In the figure, 3/8th of the length and 2/9th of the breadth is shaded. Hence, area of shaded region = 3/8 x 2/9 sq units. This gives us 1/12 sq. units as the result
Related Questions to study
Find area of the shaded region of this figure.
Find area of the shaded region of this figure.
Find area of the shaded region of this figure.
Find area of the shaded region of this figure.
Find area of the shaded region of this figure.
Find area of the shaded region of this figure.
Find area of the shaded region of this figure.
Find area of the shaded region of this figure.
Find area of the shaded region of this figure.
Find area of the shaded region of this figure.
Find area of the double shaded region of this figure.
In the given figure, three distinct colors of shade can be seen. However, on a closer look, we find out that the double shaded region has a violet color which is formed when the blue and pink color mix together and the region has dimensions 4/9 ft and 2/5 ft. hence, the area of the region is 4/9 x 2/5 square ft. Area = 8/45 sq. ft.
Find area of the double shaded region of this figure.
In the given figure, three distinct colors of shade can be seen. However, on a closer look, we find out that the double shaded region has a violet color which is formed when the blue and pink color mix together and the region has dimensions 4/9 ft and 2/5 ft. hence, the area of the region is 4/9 x 2/5 square ft. Area = 8/45 sq. ft.
Find the area of a rectangle with side lengths 
units and 
units?
Area of a rectangle is the product of its length and breadth. In the given problem, multiplying the dimensions will give us the required result. Let’s multiply 5/3 x 3/4. We get 5/4 square units.
Find the area of a rectangle with side lengths units and units?
Area of a rectangle is the product of its length and breadth. In the given problem, multiplying the dimensions will give us the required result. Let’s multiply 5/3 x 3/4. We get 5/4 square units.
Find area of the shaded region of this figure.
Area of a rectangle is the product of its length and breadth. In the given problem, multiplying the dimensions will give us the required result. Let’s multiply 4/5 x 5/7. We get 4/7 square units.The breadth of rectangle is divided into 5 equal parts and length into 7 equal parts. The shaded portion in the breadth side is 4/5 and In the length side is 5/7
Find area of the shaded region of this figure.
Area of a rectangle is the product of its length and breadth. In the given problem, multiplying the dimensions will give us the required result. Let’s multiply 4/5 x 5/7. We get 4/7 square units.The breadth of rectangle is divided into 5 equal parts and length into 7 equal parts. The shaded portion in the breadth side is 4/5 and In the length side is 5/7
Find area of the shaded region of this figure.
Area of a rectangle is the product of its length and breadth. In the given problem, multiplying the dimensions will give us the required result. Let’s multiply 3/4 x 2/5. We get 3/10 square units.
Find area of the shaded region of this figure.
Area of a rectangle is the product of its length and breadth. In the given problem, multiplying the dimensions will give us the required result. Let’s multiply 3/4 x 2/5. We get 3/10 square units.
Find the area of a rectangle with side lengths 
foot and 
foot.?
Area of a rectangle is the product of its length and breadth. In the given problem, multiplying the dimensions will give us the required result. Let’s multiply 2/3 x 1/4. We get 1/6 square feet
Find the area of a rectangle with side lengths foot and foot.?
Area of a rectangle is the product of its length and breadth. In the given problem, multiplying the dimensions will give us the required result. Let’s multiply 2/3 x 1/4. We get 1/6 square feet
Find the area of a square with side lengths of 
inch?
Area of a square is the square of its side length. Let’s square the side length. 5/8x 5/8= 25/64 square inches. Option c is the required answer.
Find the area of a square with side lengths of inch?
Area of a square is the square of its side length. Let’s square the side length. 5/8x 5/8= 25/64 square inches. Option c is the required answer.
Area of a rectangle is the product of its length and breadth. In the given problem, multiplying the dimensions will give us the required result. Let’s multiply 4/3 x 1/4. We get 1/3 square feet. Option d is the required result.
Area of a rectangle is the product of its length and breadth. In the given problem, multiplying the dimensions will give us the required result. Let’s multiply 4/3 x 1/4. We get 1/3 square feet. Option d is the required result.
Without multiplying, order the following products from the least to the greatest.
A. 
B. 
C. 
Without multiplying, order the following products from the least to the greatest.
A.
B.
C.
Mixed number of 
is,
23/5 is an example of an improper fraction. An improper fraction is the one in which the numerator is greater than or equal to the denominator.
Mixed number of is,
23/5 is an example of an improper fraction. An improper fraction is the one in which the numerator is greater than or equal to the denominator.
Subtract 
Subtraction of fraction involves the concept of LCM (Lowest common Multiplier) to make the denominators equal. In this case, denominators are already equal. Hence, we can directly subtract the numerators. We get the result 7-4=3 in the numerator and 9 in the denominator. The resultant fraction is 3/9. As we can see, this fraction can still be reduced to its simplest form. Let’s divide both the numerator and denominator by 3. This gives us 1/3.
Subtract
Subtraction of fraction involves the concept of LCM (Lowest common Multiplier) to make the denominators equal. In this case, denominators are already equal. Hence, we can directly subtract the numerators. We get the result 7-4=3 in the numerator and 9 in the denominator. The resultant fraction is 3/9. As we can see, this fraction can still be reduced to its simplest form. Let’s divide both the numerator and denominator by 3. This gives us 1/3.
