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Mathematics

Grade9

Easy

Question

Find the surface area of the figure. Round your answer to the nearest hundredth.

$73.6 m^{2}$
$362.2 m^{2}$
$36.8 m^{2}$
$181.1 m^{2}$

hint Hint:

The surface area of Pyramid = where p is the perimeter of the base , B is area of the base and l is the slant height of the pyramid.

The correct answer is: $73.6 space straight m squared$

Given from diagram the slant height of triangular pyramid is 11.1 m .
The base is a equilateral triangle with side length 4m and height 3.5 m.
$text The perimeter of base = 3 x 4 = 12 m end text text The area of the base is end text 1 half cross times 4 cross times 3.5 equals 7 space m squared U s e space t h e space s u r f a c e space a r e a space f o r m u l a comma space S u r f a c e space a r e a space equals space B space plus 1 half space cross times space P l S. A space equals space 7 space plus space 1 half space left parenthesis 12 right parenthesis left parenthesis 11.1 right parenthesis space equals space 7 space plus space 66.6 equals 73.6 space m squared$
Therefore, the surface area of the given triangular pyramid is $73.6 space straight m squared$ .

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