Graph a quadrilateral whose vertices are A(-3, -2), B(-5, -2), C(-6, 1), and D(-3, 2). Graph ABCD quadrilateral and its image when rotated 90^o about the origin

Graph a triangle ABC with vertices A(2, 1), B(4, 4), and C(8, 0). Rotate the triangle 270^o about the origin.

Graph a triangle LMN with vertices L(-5, -3), M(-3, -5), and N(0, -1). Rotate the triangle 180^o about the origin.

Find the image coordinate of the figure w.r.t 270^o rotation about the origin.

Find the image vertices of the line w.r.t 90^o rotation about the origin.

Find the coordinate of the point and its image point w.r.t 180^o rotation about the origin.

When a point (2, -4) is rotated counterclockwise about the origin. Find the coordinate after the rotation of 90^o rotation.

If you can rotate a figure more than 360^o, then the effect is the __________as rotating the figure by the angle minus 360^o.

Graph a triangle ABC with vertices A(2, 1), B(4, 4), and C(8, 0). Rotate the triangle 180^o about the origin.

Given, the vertices of a triangle ABC with vertices A(2, 1), B(4, 4), and C(8, 0).
For a rotation of 180 degrees, coordinate rule (a, b) → (-a, -b).
A(2, 1) → A’(-2, -1)
B(4, 4) → B’(-4, -4)
C(8, 0) → C’(-8, 0)
Now, graph the triangle A’B’C’.

Graph a triangle LMN with vertices L(-5, -3), M(-3, -5), and N(0, -1). Rotate the triangle 90 about the origin.

Given, the vertices of a triangle ABC with vertices L(-5, -3), M(-3, -5), and N(0, -1).
For a rotation of 90 degrees, coordinate rule (a, b) → (-b, a).
L(-5, -3) → L’(3, -5)
M(-3, -5) → M’(5, -3)
N(0, -1) → N’(1, 0)
Now, graph the triangle L’M’N’.

Find the image coordinates of the figure w.r.t 180^o rotation about the origin.

Given coordinates of the figure, A(1, 2), B(5, 2), and C(3, 5).
For a rotation of 180 degrees, coordinate rule (a, b) → (-a, -b).
A(1, 2) → A’(-1, -2)
B(5, 2) → B’(-5, -2)
C(3, 5) → C’(-3, -5)
Image coordinates of the figure are A’(-1, -2), B’(-5, -2), and C’(-3, -5).

Find the image vertices of the line w.r.t 90^o rotation about the origin.

Coordinate of the line AB, A= (1, 2) and B= (5, 2)
For a rotation of 90, coordinate rule (a, b) → (-b, a).
A(1, 2) → A’(-2, 1)
B(5, 2) → B’(-2, 5)
Image vertices of the line AB are A’(-2, 1) and B’(-2, 5).

Find the coordinate of the point and its image point w.r.t 270^o rotation about the origin.

Coordinate of point V = (-3, -2)
For a rotation of 270 degrees, coordinate rule (a, b) → (b, -a).
V(-3, -2) →  V’(-2, 3)
The coordinate V(-3, -2) and its image V’(-2, 3).

When a point (9, -2) is rotated counterclockwise about the origin. Find the coordinate after the rotation of 270^o rotation.

For a rotation of 270 degrees, (a, b) → (b, -a)
(9, -2) →(-2, -9)

When a point (5, -4) is rotated counterclockwise about the origin. Find the coordinate after the rotation of 180^o rotation.

For a rotation of 180 degrees, (a, b) → (-a, -b).
(5, -4) → (-5, 4)

From the below figure, identify the angle of rotation along with direction.

Angle of rotation is the angle that makes by the ray of center of rotation and the real object and the ray that joins the ray of center of rotation and the image object.
>>>Therefore, the angle of rotation is 105 degrees.