Question
Graph a triangle LMN with vertices L(-5, -3), M(-3, -5), and N(0, -1). Rotate the triangle 180o about the origin.
Hint:
For a rotation of 180, coordinate rule (a, b) → (-a, -b).
The correct answer is:
Given, the vertices of a triangle ABC with vertices L(-5, -3), M(-3, -5), and N(0, -1).
For a rotation of 180, coordinate rule (a, b) → (-a, -b).
L(-5,-3) → L’(5, 3)
M(-3,-5) → M’(3, 5)
N(0,-1) → N’(0, 1)
Now, graph the triangle L’M’N’.
Related Questions to study
Find the image coordinate of the figure w.r.t 270o rotation about the origin.
Find the image coordinate of the figure w.r.t 270o rotation about the origin.
Find the image vertices of the line w.r.t 90o rotation about the origin.
Find the image vertices of the line w.r.t 90o rotation about the origin.
Find the coordinate of the point and its image point w.r.t 180o rotation about the origin.
Find the coordinate of the point and its image point w.r.t 180o rotation about the origin.
When a point (2, -4) is rotated counterclockwise about the origin. Find the coordinate after the rotation of 90o rotation.
When a point (2, -4) is rotated counterclockwise about the origin. Find the coordinate after the rotation of 90o rotation.
If you can rotate a figure more than 360o, then the effect is the __________as rotating the figure by the angle minus 360o.
If you can rotate a figure more than 360o, then the effect is the __________as rotating the figure by the angle minus 360o.
Graph a triangle ABC with vertices A(2, 1), B(4, 4), and C(8, 0). Rotate the triangle 180o about the origin.
Given, the vertices of a triangle ABC with vertices A(2, 1), B(4, 4), and C(8, 0).
For a rotation of 180 degrees, coordinate rule (a, b) → (-a, -b).
A(2, 1) → A’(-2, -1)
B(4, 4) → B’(-4, -4)
C(8, 0) → C’(-8, 0)
Now, graph the triangle A’B’C’.
Graph a triangle ABC with vertices A(2, 1), B(4, 4), and C(8, 0). Rotate the triangle 180o about the origin.
Given, the vertices of a triangle ABC with vertices A(2, 1), B(4, 4), and C(8, 0).
For a rotation of 180 degrees, coordinate rule (a, b) → (-a, -b).
A(2, 1) → A’(-2, -1)
B(4, 4) → B’(-4, -4)
C(8, 0) → C’(-8, 0)
Now, graph the triangle A’B’C’.
Graph a triangle LMN with vertices L(-5, -3), M(-3, -5), and N(0, -1). Rotate the triangle 90 about the origin.
Given, the vertices of a triangle ABC with vertices L(-5, -3), M(-3, -5), and N(0, -1).
For a rotation of 90 degrees, coordinate rule (a, b) → (-b, a).
L(-5, -3) → L’(3, -5)
M(-3, -5) → M’(5, -3)
N(0, -1) → N’(1, 0)
Now, graph the triangle L’M’N’.
Graph a triangle LMN with vertices L(-5, -3), M(-3, -5), and N(0, -1). Rotate the triangle 90 about the origin.
Given, the vertices of a triangle ABC with vertices L(-5, -3), M(-3, -5), and N(0, -1).
For a rotation of 90 degrees, coordinate rule (a, b) → (-b, a).
L(-5, -3) → L’(3, -5)
M(-3, -5) → M’(5, -3)
N(0, -1) → N’(1, 0)
Now, graph the triangle L’M’N’.
Find the image coordinates of the figure w.r.t 180o rotation about the origin.
Given coordinates of the figure, A(1, 2), B(5, 2), and C(3, 5).
For a rotation of 180 degrees, coordinate rule (a, b) → (-a, -b).
A(1, 2) → A’(-1, -2)
B(5, 2) → B’(-5, -2)
C(3, 5) → C’(-3, -5)
Image coordinates of the figure are A’(-1, -2), B’(-5, -2), and C’(-3, -5).
Find the image coordinates of the figure w.r.t 180o rotation about the origin.
Given coordinates of the figure, A(1, 2), B(5, 2), and C(3, 5).
For a rotation of 180 degrees, coordinate rule (a, b) → (-a, -b).
A(1, 2) → A’(-1, -2)
B(5, 2) → B’(-5, -2)
C(3, 5) → C’(-3, -5)
Image coordinates of the figure are A’(-1, -2), B’(-5, -2), and C’(-3, -5).
Find the image vertices of the line w.r.t 90o rotation about the origin.
Coordinate of the line AB, A= (1, 2) and B= (5, 2)
For a rotation of 90, coordinate rule (a, b) → (-b, a).
A(1, 2) → A’(-2, 1)
B(5, 2) → B’(-2, 5)
Image vertices of the line AB are A’(-2, 1) and B’(-2, 5).
Find the image vertices of the line w.r.t 90o rotation about the origin.
Coordinate of the line AB, A= (1, 2) and B= (5, 2)
For a rotation of 90, coordinate rule (a, b) → (-b, a).
A(1, 2) → A’(-2, 1)
B(5, 2) → B’(-2, 5)
Image vertices of the line AB are A’(-2, 1) and B’(-2, 5).
Find the coordinate of the point and its image point w.r.t 270o rotation about the origin.
Coordinate of point V = (-3, -2)
For a rotation of 270 degrees, coordinate rule (a, b) → (b, -a).
V(-3, -2) → V’(-2, 3)
The coordinate V(-3, -2) and its image V’(-2, 3).
Find the coordinate of the point and its image point w.r.t 270o rotation about the origin.
Coordinate of point V = (-3, -2)
For a rotation of 270 degrees, coordinate rule (a, b) → (b, -a).
V(-3, -2) → V’(-2, 3)
The coordinate V(-3, -2) and its image V’(-2, 3).
When a point (9, -2) is rotated counterclockwise about the origin. Find the coordinate after the rotation of 270o rotation.
For a rotation of 270 degrees, (a, b) → (b, -a)
(9, -2) →(-2, -9)
When a point (9, -2) is rotated counterclockwise about the origin. Find the coordinate after the rotation of 270o rotation.
For a rotation of 270 degrees, (a, b) → (b, -a)
(9, -2) →(-2, -9)
When a point (5, -4) is rotated counterclockwise about the origin. Find the coordinate after the rotation of 180o rotation.
For a rotation of 180 degrees, (a, b) → (-a, -b).
(5, -4) → (-5, 4)
When a point (5, -4) is rotated counterclockwise about the origin. Find the coordinate after the rotation of 180o rotation.
For a rotation of 180 degrees, (a, b) → (-a, -b).
(5, -4) → (-5, 4)
From the below figure, identify the angle of rotation along with direction.
Angle of rotation is the angle that makes by the ray of center of rotation and the real object and the ray that joins the ray of center of rotation and the image object.
>>>Therefore, the angle of rotation is 105 degrees.
From the below figure, identify the angle of rotation along with direction.
Angle of rotation is the angle that makes by the ray of center of rotation and the real object and the ray that joins the ray of center of rotation and the image object.
>>>Therefore, the angle of rotation is 105 degrees.
When a point (a, b) is rotated 360 counterclockwise about the origin, then the coordinates of the image point will be________
Rotate the point exactly to 360 degrees to obtain the point of rotation.
When a point (a, b) is rotated 360 counterclockwise about the origin, then the coordinates of the image point will be________
Rotate the point exactly to 360 degrees to obtain the point of rotation.
When a point (a, b) is rotated 270 counterclockwise about the origin, then the coordinates of the image point will be________
Rotate the given point in the plane through 270 degrees angle of rotation to obtain the new coordinates.
When a point (a, b) is rotated 270 counterclockwise about the origin, then the coordinates of the image point will be________
Rotate the given point in the plane through 270 degrees angle of rotation to obtain the new coordinates.