Question
Michael is selling chocolate bars and orange juice in a carnival. Chocolate bars sell for $2.50 each, and orange juice sell for $3.50 each. If Michael wants to get more than $150, write an inequality showing the number of chocolate bars, b, and the number of orange juice, j, he must sell.
- 2.50b + 3.50m > 150
- 2.50b + 3.50m <150
- 2.50m + 3.50b > 150
- 2.50m + 3.50b <1
Hint:
we have to write the linear inequality in standard form for this situation. Michael is selling chocolate bars and orange juice in carnival. Chocolate sell for $2.50 each and orange juice sells for $3.50 each. He want to get more than $150. Here also chocolate bar, b and orange juice ,j. Make them as variable and write the equation.
The correct answer is: 2.50b + 3.50m > 150
Here we have to write the linear inequality in standard form.
Firstly ,He wants to get more than $150.
The chocolate bars sell for $2.50 and orange juice sells for $3.50 each
Let chocolate bar be b and orange juice be y , we can write,
2.50b + 3.50j > 150 [ in inequality more than sign is > or it is also known as greater than]
Therefore, the correct answer is 2.50b + 3.50j > 150.
or,
Since Michael wants to get more than $150, the inequality symbol will be “>”
The inequality that matches with the given situation is 2.50b + 3.50m > 150
In this question, Here we have to write the standard form of linear inequality. Always remember in inequality more than symbol is > or it is also called greater than. And make variable for that also.
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