Solve the following using the substitution method and find the value of x and y:
-x + 2y = 3
3y = -3

The correct answer is: -5, -1

In this method, the elimination of the variable can be performed by substituting the value of another variable in an equation. Hence, this method is called the elimination by substitution method.
-x + 2y = 3 and 3y = -3
Given:
-x + 2y = 3  …  (1)
         3y = -3 …(2)
The equation (2) can be written as
y = -1 … (3)
Now, substituting y = -1 in the equation (1), we get
-x + 2(-1) = 3
-x = 3 + 2
x =- 5
Therefore, the value of x is -5.
Hence, the solution for the system of linear equations is:
x = -5 and y= -1
To check whether the obtained solution is correct or not, substitute the values of x and y in any of the given equations.
Verification:
Use Equation (1) to verify the solution
-x + 2y = 3
Now, substitute x= -5 and y= -1
-(-5) + 2(-1) = 3
5 -2 = 3
3 = 3
Here, L.H.S = R.H.S
Thus, the obtained solution is correct.