Question
Coach Jhon buys 20 bats and 5 balls for his team.
A ball costs x rupees and a bat costs y rupees. John spends a total of 400 rupees on these two items.
Express x in terms of y.
- x = 80 - 4y
- x = 70 - 3y
- x = 30 - 6y
- 40 - 5y
Hint:
Express in the form of equation
The correct answer is: x = 80 - 4y
Cost of ball = x rupees
Cost of bat = y rupees
Coach Jhon buys 20 bats and 5 balls for his team.
Cost of 5balls = 5x rupees
Cost of 20bats = 20y rupees
Total amount spend = 400 rupees
5x + 20y = 400
5x = 400 -20y
x = 80 -4y
Related Questions to study
2x +y = 10 Complete the missing value in the solution to the equation. (……..,- 6 )
2x +y = 10 Complete the missing value in the solution to the equation. (……..,- 6 )
James needs to solve the system of equations using elimination.
-3x + 5y = 15 and 2x – 5y = -15
What variable should James should solve first
James needs to solve the system of equations using elimination.
-3x + 5y = 15 and 2x – 5y = -15
What variable should James should solve first
Solve the system of equations using elimination.
3x + 2y = -13 and -3x+y= 25
Solve the system of equations using elimination.
3x + 2y = -13 and -3x+y= 25
3x – y =12
3x + 5y = -6
3x – y =12
3x + 5y = -6
-5x – 2y = 9
-2x + 3y = 15
-5x – 2y = 9
-2x + 3y = 15
4x – 5y = -5
4x – 4y = 0
4x – 5y = -5
4x – 4y = 0
4x – 4y = 4
x – 3y = 5
4x – 4y = 4
x – 3y = 5
x – 5y = 20
x – y = 4
x – 5y = 20
x – y = 4
-x – y = -5
-3x + 3y = -3
-x – y = -5
-3x + 3y = -3
3y = 15
-3x – 5y = -10
3y = 15
-3x – 5y = -10
-4x – 5y = -1
-2x – 5y = 7
-4x – 5y = -1
-2x – 5y = 7
-2x – 5y = 10
-x – y = -1
-2x – 5y = 10
-x – y = -1
-5x + y = -3
5x – 4y = 12
We can solve the equation in two variable using elimination method, substitution method and cross multiplication method. In elimination method we can find the solution of the two variables by cancelling one variable by adding, multiplying or subtracting both the equations from which we will get the value of one variable. After getting the value of one variable we can put the value of that variable in equation and get the value of another variable.
-5x + y = -3
5x – 4y = 12
We can solve the equation in two variable using elimination method, substitution method and cross multiplication method. In elimination method we can find the solution of the two variables by cancelling one variable by adding, multiplying or subtracting both the equations from which we will get the value of one variable. After getting the value of one variable we can put the value of that variable in equation and get the value of another variable.
4x - 4y = 16
2x + y = -1
We can solve the equation in two variable using elimination method, substitution method and cross multiplication method. In elimination method we can find the solution of the two variables by cancelling one variable by adding, multiplying or subtracting both the equations from which we will get the value of one variable. After getting the value of one variable we can put the value of that variable in equation and get the value of another variable.
4x - 4y = 16
2x + y = -1
We can solve the equation in two variable using elimination method, substitution method and cross multiplication method. In elimination method we can find the solution of the two variables by cancelling one variable by adding, multiplying or subtracting both the equations from which we will get the value of one variable. After getting the value of one variable we can put the value of that variable in equation and get the value of another variable.
2x + y = -5
-4x + y = -5
We can solve the equation in two variable using elimination method, substitution method and cross multiplication method. In elimination method we can find the solution of the two variables by cancelling one variable by adding, multiplying or subtracting both the equations from which we will get the value of one variable. After getting the value of one variable we can put the value of that variable in equation and get the value of another variable.
2x + y = -5
-4x + y = -5
We can solve the equation in two variable using elimination method, substitution method and cross multiplication method. In elimination method we can find the solution of the two variables by cancelling one variable by adding, multiplying or subtracting both the equations from which we will get the value of one variable. After getting the value of one variable we can put the value of that variable in equation and get the value of another variable.
